Answer:
The energy stored is 1.4 x 10^-9 J.
Explanation:
Side of square, L = 10 cm = 0.1 m
Distance, d = 2 mm = 0.002 m
Electric field, E = 4000 V/m
The energy stored in the capacitor is

The capacitance is given by

Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is
.
Because the surface is flat, the radius of curvature is infinity .
The incident index is
and the transmitted index is
.
The single interface equation is 
Substituting the quantities given in the problem,

The image distance is then 
Therefore, the coin falls
in front of the target