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Firdavs [7]
3 years ago
8

A clear sheet of polaroid is placed on top of a similar sheet so that their polarizing axes make an angle of 30° with each other

. The ratio of the intensity of emerging light to incident unpolarized light is:
Physics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

\dfrac{I}{I_0}=\dfrac{3}{8}

Explanation:

Given that

Angle ,θ = 30°

From Malus law,Intensity given as

I=\dfrac{I_0}{2}cos^2\theta

Io=Intensity of unpolarized light

I=Intensity of emerging light

Now by putting the value of angle

I=\dfrac{I_0}{2}cos^2\theta

I=\dfrac{I_0}{2}cos^230^{\circ}

We know that

cos30^{\circ}=\dfrac{\sqrt{3}}{2}

I=\dfrac{I_0}{2}\times \dfrac{3}{4}

\dfrac{I}{I_0}=\dfrac{3}{8}

Therefore ratio will be \dfrac{3}{8}

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During a storm, the waves at this lighthouse were 5.0 meters tall top to bottom, and 10.0 m long. The waves impacted every 6.0 s
Sonbull [250]

Answer:

more info

Explanation:

7 0
2 years ago
The tape in a videotape cassette has a total
Softa [21]

Answer:

1.37 rad/s

Explanation:

Given:

Total length of the tape is, d= 297 m

Total time of run is, t = 2.1 hours

We know, 1 hour = 3600 s

So, 2.1 hours = 2.1 × 3600 = 7560 s

So, total time of run is, t= 7560 s

Inner radius is, r = 10\ mm = 0.01\ m


Outer radius is, R = 47\ mm = 0.047\ m


Now, linear speed of the tape is, v =\frac{d}{t}=\frac{297}{7560}=0.039\ m/s


Let the same angular speed be \omega.

Now, average radius of the reel is given as the sum of the two radii divided by 2.

So, average radius is, R_{avg}=\frac{R+r}{2}=\frac{0.047+0.01}{2}=\frac{0.057}{2}=0.0285\ m


Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,

\omega=\dfrac{v}{R_{avg}}\\\\\\\omega=\dfrac{0.039}{0.0285}\\\\\\\omega=1.37\ rad/s


Therefore, the common angular speed of the reels is 1.37 rad/s.

5 0
3 years ago
In which era did the universe’s clouds start to condense and the universe became transparent for the first time?
alukav5142 [94]

Answer:

The Universe became transparent to the light left over from the Big Bang when it was roughly 380,000 years old

Explanation:

8 0
3 years ago
A car starts out traveling at 35 m/s. The car hits the brakes and decelerates at a rate of 3 m/s^2 for 5 seconds. What Distance
Ipatiy [6.2K]
Answer:

Time needed: 2.5 s
Distance covered: 31.3 m

Explanation:

I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by

v2f=v2i−2⋅a⋅d

Isolate d on one side of the equation and solve by plugging your values

d=v2i−v2f2a

d=(15.02−10.02)m2s−22⋅2.0ms−2

d=31.3 m

To get the time needed to reach this speed, i.e. 10.0 m/s, you can use the following equation

vf=vi−a⋅t, which will get you

t=vi−vfa

t=(15.0−10.0)ms2.0ms2=2.5 s

6 0
3 years ago
What is the minimal mass of helium (density 0.18 kg/m3) needed to lift a balloon carrying two people in a basket, if the total m
Sergio039 [100]

Answer:   
 M[min] = M[basket+people+ balloon, not gas] * ΔR/R[b] 
 Î”R is the difference in density between the gas inside and surrounding the balloon. 
 R[b] is the density of gas inside the baloon.   
 ==================================== 
 Let V be the volume of helium required. 
 Upthrust on helium = Weight of the volume of air displaced = Density of air * g * Volume of helium = 1.225 * g * V   
 U = 1.225gV newtons 
 ---- 
 Weight of Helium = Volume of Helium * Density of Helium * g 
 W[h] = 0.18gV N   
 Net Upward force produced by helium, F = Upthrust - Weight = (1.225-0.18) gV = 1.045gV N  -----

 
 Weight of 260kg = 2549.7 N 
 Then to lift the whole thing, F > 2549.7 
 So minimal F would be 2549.7 
 ---- 
 1.045gV = 2549.7 
 V = 248.8 m^3   
 Mass of helium required = V * Density of Helium = 248.8 * 0.18 = 44.8kg (3sf)   
 =====   
 Let the density of the surroundings be R 
 Then U-W = (1-0.9)RgV = 0.1RgV   
 So 0.1RgV = 2549.7 N 
 V = 2549.7 / 0.1Rg   
 Assuming that R is again 1.255, V = 2071.7 m^3 
 Then mass of hot air required = 230.2 * 0.9R = 2340 kg   
 Notice from this that M = 2549.7/0.9Rg * 0.1R so   
 M[min] = Weight of basket * (difference in density between balloon's gas and surroundings / density of gas in balloon)   
 M[min] = M[basket] * ΔR/R[b]
3 0
3 years ago
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