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dsp73
3 years ago
9

Standard unit definition​

Physics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0

Answer:

Standard units are the units we usually use to measure the weight, length or capacity of objects.

Butoxors [25]3 years ago
6 0

Answer:

<em><u>THE</u></em><em><u> </u></em><em><u>SYSTEM</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>UNITS</u></em><em><u> </u></em><em><u>WHICH</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>AGR</u></em><em><u>E</u></em><em><u>E</u></em><em><u>D</u></em><em><u> </u></em><em><u> </u></em><em><u>BY</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>INTERNATIONAL</u></em><em><u> </u></em><em><u>CONVENTION</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>SCIENTISTS</u></em><em><u> </u></em><em><u>HELD</u></em><em><u> </u></em><em><u>IN</u></em><em><u> </u></em><em><u>FRANCE</u></em><em><u> </u></em><em><u>IN</u></em><em><u> </u></em><em><u> </u></em><em><u>1</u></em><em><u>9</u></em><em><u>6</u></em><em><u>0</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>CALLED</u></em><em><u> </u></em><em><u>SI</u></em><em><u> </u></em><em><u>SYSTEM</u></em><em><u>.</u></em>

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A river flows due east at 1.70 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
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Answer:

a)

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)

the required distance is 40.98 m

Explanation:

Given that;

velocity of the river u = 1.70 m/s

velocity of boat v = 14.0 m/s

Now to get the velocity of the boat relative to shore;

( north of east), we say

a² + b² = c²

(1.70)² + (14.0)² = c²

2.89 + 196 = c²

198.89 = c²

c = √198.89

c = 14.1028 m/s  

tan∅ = v/u = 14 / 1.7 =  8.23529

∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east

Therefore, the velocity of the boat relative to shore is;

v = 14.1028 m/s  

∅ = 83.0765° north of east

b)  

width of river = 340 m,

ow far downstream has the boat moved by the time it reaches the north shore in meters = ?

we say;

340sin( 90° - 83.0765°)

⇒ 340sin( 6.9235°)

= 40.98 m

Therefore, the required distance is 40.98 m

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Consider a concave spherical mirr or that has focal length f = +19.5 cm.
lidiya [134]

The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

<h3>What is concave mirror?</h3>

A concave mirror has a reflective surface that is curved inward and away from the light source.

Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.

<h3>Object distance of the concave mirror</h3>

Apply mirrors formula as shown below;

1/f = 1/v + 1/u

where;

  • f is the focal length of the mirror
  • v is the object distance
  • u is the image distance

when image height = object height, magnification = 1

u/v = 1

v = u

Substitute the given parameters and solve for the distance of the object from the mirror's vertex

1/f = 1/v + 1/v

1/f = 2/v

v = 2f

v = 2(19.5 cm)

v = 39 cm

Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.

Learn more about concave mirror here: brainly.com/question/27841226

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