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expeople1 [14]
3 years ago
11

If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa

ve frequency (in waves/second) of the waves?

Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

Explanation:

Six waves passes by under 60second interval

Since it has 6 waves,

Then, it correspond to 3 wavelength

Then,

The period of each Each wavelength is 60 / 3

Then,  period = 20seconds

From the relationship between frequency and period

f = 1 / T

f = 1 / 20

f = 0.05 Hz

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4 years ago
Normal body temperature. the average normal body temperature measured in the mouth is 310 k . what would celsius and fahrenheit
faltersainse [42]
The question is simply asking us to convert one unit, in this case temperature, to another unit. To do this, we need conversion factors to multiply, divide or relate to the original measurement. We do as follows:

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310 - 273.15 = 36.85 degrees celsius

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7 0
3 years ago
Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ

Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference

For the separation of the lines we use trigonometry

        tan θ = sin θ / cos θ = y / x

In interference experiments the angle is very small

          tan θ = sin θ = y / x

         d y / x = m λ

a) and b) We apply the equation to the first laser

          λ = d / 20

          d y / x = m d / 20

          y = m x / 20

          y = 1 4.80 / 20

          y = 0.24 m

The second laser

        λ = d / 15

          d y / x = m d / 15

          y = m x / 15

          y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

They ask us for the second maximum m = 2

            y₂ = 2 4.8 / 20

            y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

         y₃ = (m + ½) x / 15

         m = 3

         y₃ = (3 + ½) 4.8 / 15

         y₃ = 1.12 m

        Δy = 1.12 - 0.48

        Δy = 0.64 m

4 0
3 years ago
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