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expeople1 [14]
3 years ago
11

If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa

ve frequency (in waves/second) of the waves?

Physics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

Explanation:

Six waves passes by under 60second interval

Since it has 6 waves,

Then, it correspond to 3 wavelength

Then,

The period of each Each wavelength is 60 / 3

Then,  period = 20seconds

From the relationship between frequency and period

f = 1 / T

f = 1 / 20

f = 0.05 Hz

You might be interested in
. An object whose mass is 375 lb falls freely under the influence of gravity from an initial elevation of 253 ft above the surfa
lozanna [386]

Answer:

(a) Vf = 128 ft/s

(b) K.E = 122.8 Btu

Explanation:

(a)

In order to find the velocity of the object just before striking the surface of earth or the final velocity, we use 3rd equation of motion:

2gh = Vf² - Vi²

where,

g = 32.2 ft/s²

h = height = 253 ft

Vf = Final Velocity = ?

Vi = Initial Velocity = 10 ft/s

Therefore,

(2)(32.2 ft/s²)(253 ft) = Vf² - (10 ft/s)²

16293.2 ft²/s² + 100 ft²/s² = Vf²

Vf = √(16393.2 ft²/s²)

<u>Vf = 128 ft/s</u>

<u></u>

(b)

The kinetic energy of the object before it hits the surface of earth is given by:

K.E = (0.5)(m)(Vf)²

where,

m = mass of object = 375 lb

K.E = Kinetic energy of object before it strikes the surface of earth = ?

Therefore,

K.E = (0.5)(375 lb)(128 ft/s)²

K.E = 3073725 lb.ft²/s²

Now, converting this to Btu:

K.E = (3073725 lb.ft²/s²)(1 Btu/25037 lb.ft²/s²)

<u>K.E = 122.8 Btu</u>

3 0
3 years ago
Look at the graph. What is the slope of the line?
NeTakaya

For the first hour, the slope is zero.

After that, the slope is -2 miles per hour.

7 0
2 years ago
A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for
Sonja [21]

Answer:

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

8 0
3 years ago
What is the second most abundant element in the universe? <br> a. h <br> b. c <br> c. fe <br> d. he
Andru [333]
D I think I'm not sure!?.
7 0
3 years ago
Would it be true that if you double the distance of an astronaut from a planet, the gravitational pull between them would be hal
velikii [3]

Answer:

Yes

Explanation:

Newton's law of universal gravitation is usually stated that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses(m1 and m2) and inversely proportional to the square of the distance between their centers(r).

F = Gm1m2/r²

This is a general physical law derived from

empirical observations by what Isaac Newton called inductive reasoning.

when distance is doubled the gravitational force will be reduced by quarter not half.

5 0
3 years ago
Read 2 more answers
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