Answer: 30 metres
Explanation:
Initial velocity of object = 120m/s
Time taken = 4.0s
Distance covered by object = ?
Recall that distance = (Change in velocity / Time taken)
Distance = (120m/s)/4.0s
= (120m/s) / 4.0s
= 30m
Thus, the object will be 30 metres high
The force between the molecules involved in the bond is 6. 426 *10^-11 Newton
<h3>How to determine the force</h3>
Using the formula:
F = K[q1 x q2]/D^2
where K is coulombs constant =9 *10 ^9 Nm^2/C^2.
q1 and q2 = charges = 1.60x10 -20C
d = distance between the charges = 2x10 -10 m
Substitute the values into the formula
F =
F = 
F = 
F =
Newton
Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton
Learn more about electrostatic force here:
brainly.com/question/8424563
#SPJ1
Answer:
The final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
Explanation:
Let us consider east as positive direction and west as negative direction .
Given
mass of puck 1 , 
mass of puck 2 , 
initial speed of puck 1 , 
initial speed of puck 2 , 
Final speed of puck 1 and puck 2 be
respectively
Apply conservation of linear momentum

=>
=>
-----(A)
Since collision is perfectly elastic , coefficient restitution e=1

=>
------(B)
From equation (A) and (B)

and 
Thus the final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
Correct Question:-
A jack exerts a vertical force of 4.5 × 10³
newtons to raise a car 0.25 meter. How much
work is done by the jack?

Given :-



To find:-


Solution:-
we know :-


So:-



























Answer:

Explanation:
<u>Given:</u>
Force = f = 60 N
Mass = m = 12 kg
<u>Required:</u>
Acceleration = a = ?
<u>Formula:</u>
F = ma
<u>Solution:</u>
Rearranging formula
a = F / m
a = 60 / 12
a = 5 ms⁻²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>