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Inessa [10]
3 years ago
5

Why does temperature increase with altitude through the stratosphere? The stratosphere is closest to the sun. The ozone layer is

found in the stratosphere. All layers of the atmosphere increase in temperature with altitude. The air molecules are closer together in the upper stratosphere.
Chemistry
2 answers:
lukranit [14]3 years ago
8 0
Temperature increase with altitude through the stratosphere because "<span>The ozone layer is found in the stratosphere".

Stratosphere is the second layer of the atmosphere of the Earth. 20% of the mass of the atmosphere is found in this layer. 
</span><span>The temperature of the </span>stratosphere increases as the altitude increases due to the presence of the ozone layer in it as the ozone layer absorbs the ultraviolet radiations of the Sun which causes an increase in the temperature of this layer.
vaieri [72.5K]3 years ago
5 0

Temperature increase with altitude through the stratosphere because "The ozone layer is found in the stratosphere".

Stratosphere is the second layer of the atmosphere of the Earth. 20% of the mass of the atmosphere is found in this layer.

The temperature of the stratosphere increases as the altitude increases due to the presence of the ozone layer in it as the ozone layer absorbs the ultraviolet radiations of the Sun which causes an increase in the temperature of this layer.

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Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a
djverab [1.8K]

solution:

the change in the boiling point is given as,

dTbp =2.30°c

elevation constant for the solvent is given by,

kb=0.512°c/m

molality=\frac{dTBP}{KB\times m}\\=\frac{2.30}{0.512c/m}

= 4.49m

8 0
3 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
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melomori [17]
Stored water is gravitational
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3 years ago
[20 Points!] The solubility product constant of calcium hydroxide is 6.5 x 10^-6. If 0.10 mol of sodium hydroxide is added to 1
sleet_krkn [62]
For Ca(OH)2, Ksp = [Ca2+][OH-]^2
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).

6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
[Ca2+] = 0.00065 M

The maximum concentration of [Ca2+] is 0.00065 M, and you have 0.0010 M Ca(OH)2, so you’ll end up with 0.00065 M Ca2+ in solution.
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Which of the followings statements accurately describes renewable energy sources?
grigory [225]
Number one is the correct answer
8 0
4 years ago
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