Answer:
![M_{per}= 52.86](https://tex.z-dn.net/?f=M_%7Bper%7D%3D%2052.86%20)
![W_{per}=47.14](https://tex.z-dn.net/?f=W_%7Bper%7D%3D47.14%20)
Explanation:
<u>First mixture</u>:
40 wt% methanol - 60 wt% water 200 kg
![m_{met1}=200 kg * 0.4= 80 kg](https://tex.z-dn.net/?f=m_%7Bmet1%7D%3D200%20kg%20%2A%200.4%3D%2080%20kg)
![m_{wat1}=200 kg * 0.6= 120 kg](https://tex.z-dn.net/?f=m_%7Bwat1%7D%3D200%20kg%20%2A%200.6%3D%20120%20kg)
<u>Second mixture</u>:
70 wt% methanol - 30 wt% water 150 kg
![m_{met2}=150 kg * 0.7= 105 kg](https://tex.z-dn.net/?f=m_%7Bmet2%7D%3D150%20kg%20%2A%200.7%3D%20105%20kg)
![m_{wat2}=150 kg * 0.3= 45 kg](https://tex.z-dn.net/?f=m_%7Bwat2%7D%3D150%20kg%20%2A%200.3%3D%2045%20kg)
Final mixture:
![m_{metF=80 kg + 105 kg= 185 kg](https://tex.z-dn.net/?f=m_%7BmetF%3D80%20kg%20%2B%20105%20kg%3D%20185%20kg)
![m_{watF}=120 kg + 45 = 165 kg](https://tex.z-dn.net/?f=m_%7BwatF%7D%3D120%20kg%20%2B%2045%20%3D%20165%20kg)
![M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86](https://tex.z-dn.net/?f=M_%7Bper%7D%3D%5Cfrac%7B185%20kg%7D%7B185%20kg%20%2B%20165%20kg%7D%2A100%3D%2052.86%20)
![W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14](https://tex.z-dn.net/?f=W_%7Bper%7D%3D%5Cfrac%7B165%20kg%7D%7B185%20kg%20%2B%20165%20kg%7D%2A100%3D47.14)
If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.
The alveoli are surrounded<span> by tiny blood vessels, called capillaries. The </span>alveoli<span> and capillaries both have very thin walls, which allow the oxygen to pass from the </span>alveoli<span>to the blood. The capillaries then connect to larger blood vessels, called veins, which bring the oxygenated blood from the lungs to the heart.</span>
Answer: The pair that consists of a base and its conjugate acid in that order.![NH_3/NH_4^+](https://tex.z-dn.net/?f=NH_3%2FNH_4%5E%2B)
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
![H_3PO_4\rightarrow H_PO_4{2^-}+2H^+](https://tex.z-dn.net/?f=H_3PO_4%5Crightarrow%20H_PO_4%7B2%5E-%7D%2B2H%5E%2B)
![H_2CO_3\rightarrow HCO_3^-+H^+](https://tex.z-dn.net/?f=H_2CO_3%5Crightarrow%20HCO_3%5E-%2BH%5E%2B)
![NH_3+H^+\rightarrow NH_4^+](https://tex.z-dn.net/?f=NH_3%2BH%5E%2B%5Crightarrow%20NH_4%5E%2B)
is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms
which is a conjugate acid.
Answer:
B. They will conserve energy during reproduction
Explanation: