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Alex17521 [72]
3 years ago
9

What is the separation distance, in meters, between masses m1 = 15 x 107 kg and m2 = 62 x 107 kg when the gravitational force be

tween them is F = 7 x 102 N? Please round your answer to the nearest whole number (integer).\
Physics
1 answer:
nalin [4]3 years ago
3 0

Answer:

94.1 m

Explanation:

From Coulombs law,

F  = Gm1m2/r²................... Equation 1

where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.

Make r the subject of the equation,

r = √(Gm1m2/F)................. Equation 2

Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 2

r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)

r √(886.16×10)

r √(88.616×10²)

r = 9.41×10

r = 94.1 m.

Hence the distance of separation = 94.1 m

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Answer:

Intensity of the light (first polarizer) (I₁) = 425 W/m²

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Explanation:

Given:

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Intensity of the light (first polarizer) (I₁) = 950 / 2

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b. Intensity of the light (second polarizer)

Intensity of the light (second polarizer) (I₂) = (I₁)cos²θ

Intensity of the light (second polarizer) (I₂) = (425)(0.1786)

Intensity of the light (second polarizer) (I₂) = 75.905 W/m²

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Answer:

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x=-7/5     (divide both sides by 5)

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The correct answer is -

B. The velocity would double (v = 2v).

C. The wavelength would be half (λ = λ/2).

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A wave has a speed or velocity that is related to the wavelength of the wave and the frequency of the wave and this relationship can be represented by the following equation-

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