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Ksenya-84 [330]
2 years ago
13

A battery with 20% of its full capacity is connected to a charger. Every minute that passes, an additional 5% of its capacity is

charged. Graph the relationship between the battery’s capacity and the time
Mathematics
2 answers:
Masja [62]2 years ago
3 0

Answer:

Step-by-step explanation:

y = 5x + 20

Start at (0, 20).

Then plot a point at (1, 25).

The line should be going through points (2, 30), (3, 35), (4, 40), (5, 45), etc.

For every time the x number goes up, the y number goes up 5 times for the 5%.

Reptile [31]2 years ago
3 0

Answer:

Given,

The original percentage of battery = 20 %,

Also, Every minute that passes, an additional  5%,

So, the increment in percentage after x minutes = 5x percentage

Thus, the final battery after x minutes = ( 20 + 5x ) %

Let y represents the total percentage of battery after x minutes,

⇒ y = 20 + 5x

Which is the required function that shows the given situation.

For graphing,

y = 20 + 5x is a line having x-intercept = (-4,0)

And, y-intercept = (0,20)

Also, battery's capacity and time can not be negative,

⇒ x ≥ 0 , y ≥ 0

Read more on Brainly.com - brainly.com/question/9880903#readmore

Step-by-step explanation:

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*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle
Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

  • On the extension of the side BC , draw a line segment CD ≅ CA
  • Draw the segment AD
  • The line segment CE is the angle bisector of ∠ACB
  • The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

  side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

#LearnwithBrainly

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