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Mashutka [201]
3 years ago
6

In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur

ther step to isolate it. Let's say we now have
3C+4D = 5
2C+5D = 2
None of these terms has a coefficient of 1. Instead, we'll pick the variable with the smallest coefficient and isolate it. Move the term with the lowest coefficient so that it's alone on one side of its equation, then divide by the coefficient. Which of the following expressions would result from that process?
a. C=53−43D
b. C=1−52D
c. D=25−25C
d. D=54−34C
Physics
1 answer:
Flura [38]3 years ago
5 0

Answer:

a) C = (5-4D)/3

Explanation:

Given the simultaneous equation

3C+4D = 5 .... 1

2C+5D = 2 .... 2

In order to isolate one of the variables, we will make one of the variables in any of the equation.

Using equation 1:

3C+4D = 5

Make C the subject of the formula:

Subtract 4D from both sides of the equation.

3C+4D-4D= 5-4D

3C = 5-4D

Divide both sides by 3:

3C/3 = (5-4D)/3

C = (5-4D)/3

Hence the expression that would result from the process is C = (5-4D)/3

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Answer:

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Explanation:

4 0
3 years ago
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All of the following equations are statements of the ideal gas law except
elena55 [62]

Answer:

a. P = nRTV

Explanation:

The question is incomplete. Here is the complete question.

"All of the following equations are statements of the ideal gas law except a. P = nRTV b. PV/T = nR c. P/n = RT/v d. R = PV/nT"

Ideal gas equation is an equation that describes the nature of an ideal gas. The molecule of an ideal gas moves at a particular velocity depending on the temperature. This gases collides with one another elastically. The collision that an ideal gas experience is a perfectly elastic collision.

The ideal gas equation is expressed as shown:

PV = nRT where:

P is the pressure of the gas

V is the volume

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R is the ideal gas constant

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The remaining option will results to an ideal gas equation if they are cross multipled.

7 0
4 years ago
If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
steposvetlana [31]

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

3 0
3 years ago
When sound is created it travels to the car through a
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