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olga2289 [7]
3 years ago
11

Calculate the speed of a car that travels a distance of 2.4km in 2 minutes ​

Physics
1 answer:
hammer [34]3 years ago
3 0

Answer:

72 kilometres per hour

Explanation:

The formula for calculating speed is distance/time.

So to work this out you would convert 2 minutes into hours. You would divide 2 by 60 to convert it into hours. This is because the standard unit for speed with kilometres is kilometres per hour. Then  you would divide 2.4 by that.

1)Divide 2 by 60:

2/60=0.0333333

2) Divide 2.4 by 0.0333333.

2.4/0.0333333=72.00007

3) Round it.

72km/h

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When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne
iren2701 [21]

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. \frac{E}{2} fraction is blocked by 10 cm thickness

then remaining radiation is \frac{E}{2}

another 10 cm thickness will block the remaining half radiation i.e. \frac{1}{2}\times \frac{E}{2}=\frac{E}{4}

so total 75 % radiation will be blocked

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3 years ago
Sonar question: A person's yells into a deep well, sending a sound wave that travels at a speed of 50 m/s. The echo is heard in
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3 years ago
The total weight of a car with passengers is 30,000N. The area of contact of each of the four tyres with the ground is 0.025m2.
vlabodo [156]

Answer:

<em>The minimum pressure car tire pressure is 300,000 Pa</em>

Explanation:

<u>Pressure</u>

It's a measure of the force exerted by an object per unit surface:

\displaystyle P=\frac{F}{A}

Where F is the force applied on a surface area A.

We are given the total weight of a car with passengers as Ft=30,000 N and we also know the area of contact of each tire with the ground as A=0.025 m^2.

The minimum pressure each tire can have is when the total weight is evenly distributed in all four tires, thus F=Ft/4=7,500 N.

Calculating the pressure:

\displaystyle P=\frac{7,500}{0.025}

P=300,000 Pa

The minimum pressure car tire pressure is 300,000 Pa

7 0
2 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
leonid [27]

Answer:

KE_A=33\ J

KE_B=99\ J

Explanation:

Given:

Let mass of the particle B be, m_B=m

then the mass of particle A, m_A=3m

Energy stored in the compressed spring, E=132\ J

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132

3m.v_A^2+m.v_B^2=264 .............................(1)

<u>Using the conservation of linear momentum:</u>

m_A.v_A+m_B.v_B=0

3m.v_A+m.v_B=0 .............................(2)

Put the value of v_A from eq. (2) into eq. (1)

3m\times (\frac{-v_B}{3})^2+m.v_B^2=264

v_B^2=\frac{198}{m}  ...........................(3)

<u>Now the kinetic energy of particle B:</u>

KE_B=\frac{1}{2}\times m_B\times v_B^2

KE_B=\frac{1}{2}\times m\times \frac{198}{m}

KE_B=99\ J

Put the value of v_B^2 form eq. (3) into eq. (1):

v_A^2=\frac{22}{m}

<u>Now the kinetic energy of particle A:</u>

<u />KE_A=\frac{1}{2}m_A.v_A^2<u />

<u />KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}<u />

KE_A=33\ J

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3 years ago
What is the direction of the magnetic field at point Z?
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The direction of the magnetic field at point Z ; INTO THE SCREEN

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3 years ago
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