Question

Ohm’s Law is represented by the equation I=V/R. Explain how the current would change if the amount of resistance decreased and the voltage stayed the same. (HINT: try plugging numbers into the equation for R, but make sure V stays the same. Then describe what happens to I(current) Click HEREto view a video that will help you

Answer 1

Answer:

The current will increase with reduction in the resistance.

Explanation:

Electrical resistance reduces the flow of electricity through a conductor just like friction reduces our speed. The higher the resistance the harder it will be for the current to flow and vice versa, hence, higher resistance produces a smaller current if the voltage is held constant. The voltage is the electrical drive.

Answer 2

Answer:

Current will increase.

Explanation:

Lets first solve for current in terms Voltage V and resistance R.

$I = \frac{V}{R}$

now if you make voltage smaller and smaller the voltage will increase, how.?

Let me show it to you by plugging in some numbers,

V = 10 Volts (constant) and R = 5Ohms.

I = $\frac{10}{5} = 2Amperes$

Now lets take R = 2 Ohms

I = $\frac{10}{2} = 5Amperes.$

5 is obiviously greater than 2, so we can conclude that as the resistance decreases with constant voltage the current increases in return.