Ohm’s Law is represented by the equation I=V/R. Explain how the current would change if the amount of resistance decreased and t
he voltage stayed the same. (HINT: try plugging numbers into the equation for R, but make sure V stays the same. Then describe what happens to I(current) Click HEREto view a video that will help you
2 answers:
Answer:
The current will increase with reduction in the resistance.
Explanation:
Electrical resistance reduces the flow of electricity through a conductor just like friction reduces our speed. The higher the resistance the harder it will be for the current to flow and vice versa, hence, higher resistance produces a smaller current if the voltage is held constant. The voltage is the electrical drive.
Answer:
Current will increase.
Explanation:
Lets first solve for current in terms Voltage V and resistance R.
now if you make voltage smaller and smaller the voltage will increase, how.?
Let me show it to you by plugging in some numbers,
V = 10 Volts (constant) and R = 5Ohms.
I =
Now lets take R = 2 Ohms
I =
5 is obiviously greater than 2, so we can conclude that as the resistance decreases with constant voltage the current increases in return.
You might be interested in
Answer:
James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down
Explanation:
Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards
so here we can say
Upwards force = downwards Force + weight of snow
while if we find the other force which is acting downwards
then for that force we can say that net torque must be balanced
so here we have
so here we have
so here we can say that upward force by which we push up is always more than the downwards force
Answer:
<h2>Refer the attachment for answer and explanation please</h2>Explanation:
This might surely help you ☺️❤️
Answer:
She will make the jump.
Explanation:
We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
First we will consider horizontal motion of stunt women
Displacement = 77 m, Initial velocity = 28 cos 15 = 27.05 m/s, acceleration = 0
Substituting
So she will cover 77 m in 2.85 seconds
Now considering vertical motion, up direction as positive
Initial velocity = 28 sin 15 = 7.25 m/s, acceleration =acceleration due to gravity = -9.8 , time = 2.85
Substituting
So at time 2.85 stunt women is 10.11 m below from starting position, far side is 25 m lower. So she will be at higher position.
So she will make the jump.
Answer:
E = (-3.61^i+1.02^j) N/C
magnitude E = 3.75N/C
Explanation:
In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:
(1)
Where the minus sign means that the electric field point to the charge.
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q = -4.28 pC = -4.28*10^-12C
r: distance to the charge from the point P
The point P is at the point (0,9.83mm)
θ: angle between the electric field vector and the x-axis
The angle is calculated as follow:
The distance r is:
You replace the values of all parameters in the equation (1):
The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C