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ANTONII [103]
3 years ago
12

Round this number to two significant figures. 634

Chemistry
2 answers:
Aneli [31]3 years ago
7 0
The answer to this is 630
loris [4]3 years ago
4 0

Answer : The correct answer is 630.

Explanation :

The following rules are used to round off a number to the required number of significant figures:

(1) If the rightmost digit to be removed is more than 5, the preceding number is increased by one.

(2) If the rightmost digit to be removed is less than 5, the preceding number is not changed.

(3) If the rightmost digit to be removed is 5, then the preceding number is not changed if it is an even number but it is increased by one if it is an odd number.

As we are given, 634

In the given number, there are 3 significant figures. Now we have to convert it into 2 significant figures.

According to the rules, round off the given measurement in 2 significant figures as 630 because last number i.e 4 is less than number 5 so, last digit become 0.

Therefore, the correct answer is 630.

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Rama09 [41]
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4 0
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Does cm² mean with the power of two?
sweet [91]

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4 0
4 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

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6 0
3 years ago
Read 2 more answers
Which atom has a change of oxidation number of +4 in the pictured redox reaction?
SpyIntel [72]

Answer:

The answer to your question is the letter d. S

Explanation:

Data

Change of +4 in the oxidation number

Chemical reaction

               K₂Cr₂O₇  +  H₂O  +  S  ⇒   KOH  +  Cr₂O₃  +  SO₂    

Process

1.- Calculate the oxidation numbers following the rules.

Some rules

  H = +1       O = -2    Alkali metals = + 1    Alkali earth metals = +2    

K₂⁺¹Cr₂⁺⁶O₇⁻²  +  H₂⁺¹O⁻²  +  S⁰  ⇒   K⁺¹O⁻²H⁺¹  +  Cr₂⁺³O₃⁻²  +  S⁺⁴O₂⁻²    

Elements that changed their oxidation numbers

                       Cr₂⁺⁶   ---------------- Cr₂⁺³

                       S⁰       --------------- S⁺⁴

                     

 

3 0
3 years ago
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