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Harman [31]
3 years ago
14

An atom that no longer has a beutral charge is called a(n)____.

Physics
1 answer:
Simora [160]3 years ago
8 0

An atom that no longer has a neutral charge is called an ion

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What does itmean to have an acceleration of 8 m/s2
Masteriza [31]

Answer:

The answer is option A.

You speed up 8 m/s every second

Hope this helps you

8 0
3 years ago
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A mother and her young child want to play on a seesaw at a playground. The child sits on the end of one side of the seesaw. Wher
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Answer:middle

Explanation:

Because it will make the seasaw balanced

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3 years ago
As a pendulum bob swings back and forth several times, the maximum height it reaches becomes less and less.
Ymorist [56]

Answer:

A or B

Explanation:

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3 years ago
What happens to the object if the line crosses the x-axis from the positive portion of a velocity versus time diagram?
stealth61 [152]

Answer:

A velocity time graph shows the change of velocity of an object with respect ot time. If the slope of the graph is increasing in the postive region, it means that the velocity is changing, if the slope is decreasing, it means the the velocity is decreasing, but the object is moving in the same direction (positve direction).

If this slope intersects the graph at x-axis, it means that the body has 0 velocity and has become still. After that, if the line enters in the negative region, it means that its velocity is started to increases again, but the body is movinging in the opposite direction (negative direction)

7 0
3 years ago
A 6.0-kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
jeka57 [31]

Answer:

a. 3.1 m/s^2

Explanation:

The equation of the forces along the directions parallel and perpendicular to the slope are:

- Along the parallel direction:

mg sin \theta - \mu_k R = ma

where :

m = 6.0 kg is the mass  of the box

g = 9.8 m/s^2 the acceleration of gravity

\theta=39^{\circ}  is the angle of the slope

\mu_k = 0.40 is the coefficient of friction

R is the normal reaction  

a is the acceleration

- Along the perpendicular direction:

R-mg cos \theta =0

From the 2nd equation, we get an expression for the reaction force:

R=mg cos \theta

And substituting into the 1st equation, we can find the acceleration:

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta =(9.8)(sin 39^{\circ})-(0.40)(9.8)(cos 39^{\circ})=3.1 m/s^2

6 0
3 years ago
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