Explanation:
Given that,
Initial speed of the man's hand, u = 3.75 m/s
Finally, the hand comes to rest, v = 0
Time interval, t = 2.75 ms
Total mass of the forearm and the hand is, m = 1.75 kg
To find,
The magnitude of force exerted on the leg
Solution,
We know that the force exerted from one object to another is given by using second law of motion as :
F = m × a
a is the acceleration of the object
F = -2386.36 N
Therefore, the force exerted on the leg is 2386.36 N.
As per Faraday's law of induction we know that induced EMF in a conducting closed loop is equal to rate of change in flux in that loop
So here we have
now when we move out a coil from magnetic field then in this case there will be EMF induced in that coil as here magnetic flux is changing with time linked with the coil.
Now this induced voltage will remain constant if coil is moved out uniformly
But it will not remain constant if coil is moved out with non uniform speed
So this statement is not always true
so answer must be
<u>FALSE</u>