On classical Hall mobility: In a semiconductor sample, the Hall probe region has a dimension of 0.5 cm by 0.25 cm by 0.05 cm thi
ck. For an applied electric field of 1.0 V/cm, 20 mA current flows (through the long side) in the circuit. When a 10 kG magnetic field is applied, a Hall voltage of 10 mV is developed. What is the Hall mobility of the sample and what is the carrier density
1 answer:
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Answer:
Explanation:
Given
height of grand canyon is
Rock is dropped i.e. initial velocity is zero
Using Equation of motion
h=height
u=initial velocity
a=acceleration
t=time
here a=acceleration due to gravity
Answer:
244.64m
Explanation:
First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:
After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:
1. The velocity will start to decrease untill it reaches 0m/s.
2. Then, the velocity will start to increase at the rate of the acceleration.
The distance that the ball travels in the first phase can be found with the following expression:
Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:
Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:
Then, the time of the second phase will be:
Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:
V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:
So, the total distance covered by this object in meters will be the sum of all the distances we found:
Here,
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
/86400)^2 * 6.4*10^6
=0.034 m/s²
m=80 kg
R= 6.4*10^6 m
and t=24*3600=86400 s
Centripetal acceleration:
a=ω²r
=(2
=0.034 m/s²