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Ugo [173]
4 years ago
13

On classical Hall mobility: In a semiconductor sample, the Hall probe region has a dimension of 0.5 cm by 0.25 cm by 0.05 cm thi

ck. For an applied electric field of 1.0 V/cm, 20 mA current flows (through the long side) in the circuit. When a 10 kG magnetic field is applied, a Hall voltage of 10 mV is developed. What is the Hall mobility of the sample and what is the carrier density

Physics
1 answer:
lbvjy [14]4 years ago
5 0

Answer:

hall mobility = 139.8 x 10 ∧3

carrier density = 83.1 x 10 ∧14

Explanation:

The pictures attached below shows the full explanation

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3 years ago
Two objects having masses m1 and m2 are connected to each other as shown in the figure and are released from rest. There is no f
tankabanditka [31]

Answer:m_1g

Explanation:

Given

Two masses m_1  and m_2  is released and there is tension T in the string

Suppose a is the acceleration of the system

Therefore from Diagram

For m_1

T-m_1g=m_1a

T=m_1(g+a)------1

for m_2 body

m_2g-T=m_2a

T=m_2(g-a)-------2

From above two Equation it is said that Tension is greater than m_1g and less than m_2g

m_1g

4 0
3 years ago
Read 2 more answers
Suppose the electrostatic force between two electrons is F. What is the electrostatic force between an electron and a proton
mars1129 [50]

Answer:

D. −F

Explanation:

the rest of the answers are

2/3F

The force is represented as a positive quantity and is repulsive.

Electrostatic force is inversely proportional to the square of the distance.

The direction of the force changes, and the magnitude of the force quadruples.

hope this helps sorry if i was too late! :)

8 0
3 years ago
A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is to have the actor fall on hi
IgorC [24]

Answer:

m=17.79Kg

Explanation:

In this process energy must be conserved. On the initial stage, there will be only gravitational potential energy, while on the final stage there will be only elastic potential energy, so they will be equal. We write this as:

U_g=U_e

Which is the same as:

mgh=\frac{k \Delta x^2}{2}

So we can obtain our mass from there, and for our values:

m=\frac{k \Delta x^2}{2gh}=\frac{(65144 N/m)(0.1333m)^2}{2(9.8m/s^2)(3.32m)}=17.79Kg

4 0
4 years ago
A railroad car with a mass of 30,000 kg is moving at 2.0 m/s when it runs into an at-rest freight car with an equal mass. The ca
11Alexandr11 [23.1K]
The total momentum of the system is preserved through the collision.

Note that momentum is
P = m*v
where m = mass
v = velocity.

Initial momentum:
P1 = (30000 kg)*(2 m/s) = 60000 (kg-m)/s for the moving car
P2 = 0 for the starionary car.

Final momentum:
P3 = (30000 + 30000)*v = 60000v (kg-m)/s

Because momentum is preserved,
P3 = P1 + P2
60000v = 60000
v = 1 m/s
The final velocity is 1 m/s.

Answer: 1.0 m/s
4 0
3 years ago
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