Use the atomic weights of H and Cl to calculate the answer to
question 7. For H, it is 1. For Cl it is 35.45.
<span>The
ratio of H to Cl in HCL is 1:1. Therefore, 16.2 grams of H means that there
will be 16.2 * 35.45 grams of Cl within the resulting HCl. Therefore, the grams
of HCl will be 16.2 grams + 574.29 grams = 590.5 grams of HCl</span>
To determine the masses of each component, we need to know the concentration first in terms of molality which is mol per mass of solution. Assuming the density of the solution is equal to that of water we would find:
molality = 0.160 mol KBr / L ( 1 L / 1 kg solution ) = 0.160 mol KBr / kg solution
mass KBr = 0.160 mol KBr / kg solution (.0750 kg solution ) ( 119 g KBr / mol KBr ) = 1.428 g KBr
mass solvent = 75 - 1.428 = 73.572 g water
Answer : The net ionic equation will be,

Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation between zinc and hydrochloric acid will be,

The ionic equation in separated aqueous solution will be,

In this equation,
is the spectator ion.
By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
