Answer:
Total BF for the interior wall is 7.50BD
Explanation:
Given Data:
· Size of stud = 2” x 6”
· Height of Wall = 8 ft
· Top plates = 2
· Bottom Plate = 1
BF stands for board feet in lumber/wood terminology. It is the unit of volume.
1 BF (Board feet) = 1 ft x 1 ft x 1 inch
Since there are total three plates at top and bottom, we have to deduct their thickness from wall height to calculate height of stud.
Height of stud = 8’ – 3 x 2” = 7’6” = 7.5 ft
Board feet of one stud = 7.50 6/12 x 2 = 7.50 BD
Total BF for the interior wall is 7.50BD
Answer:
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Explanation:
given data
angles φ = 43.1 degrees
angles λ = 47.9 degrees
shear stress = 20.7 MPa (3000 psi)
stress σ = 45 MPa (6500 psi)
solution
we have given shear stress so first we calculate here resolved shear stress that is express as
resolved shear stress = σ cosφ cosλ .................1
here σ is stress and φ and λ are angles given
so put here value we get
resolved shear stress = σ cosφ cosλ
resolved shear stress = 45 cos(43.1) cos(47.9)
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Answer
diameter of parking lot = 18 in
flowrate = 10 ft³/s
pressure drop = 100 ft
using general equation



taking f = 0.0185
at Z₁ = Z₂

ΔP = 0.266 psi
b) when flow is uphill z₂-z₁ = 2


c) When flow is downhill z₂-z₁ = -2


Explanation:
Below is an attachment containing the solution.
The characteristics that can be observed when a headwind shears to be a constant tailwind are:
- Pitch attitude: decreases.
- Required thrust: increased then reduced.
- Vertical Speed: increases.
- Indicated airspeed (IAS): decreases, then increases to approach speed.
<h3>What is thrust?</h3>
Thrust can be defined a force that moves an aircraft or a flying machine through the air, especially in the direction of the motion.
<h3>The importance of thrust.</h3>
Generally, thrust is used in aeronautic engineering to achieve the following:
- To overcome the weight of a rocket.
- To overcome the drag of an aircraft.
- To maintain indicated airspeed (IAS).
- To maintain glide slope being flown at.
Some of the characteristics that can be observed when a headwind shears to be a constant tailwind are:
- Pitch attitude: decreases.
- Required thrust: increased then reduced.
- Vertical Speed: increases.
- Indicated airspeed (IAS): decreases, then increases to approach speed.
Read more on thrust here: brainly.com/question/20068220