Answer:
electron-electron repulsion
Explanation:
When electrons add into valence shell of neutral elements, the element assumes a negative oxidation state. With this, the number of electrons having (-) charges will be larger than the number of protons having positive (+) charges. As a result, the extra electrons repel one another (i.e., like charges repel) and a larger radius is the result.
In contrast, when cations are formed, electrons are removed from the valence level (oxidation) producing an element having a greater number of protons than electrons. The larger number of protons will function to attract the electron cloud with a greater force that results in a contraction of atomic radius and a smaller spherical volume than the neutral unionized element.
To visualize, see attached chart that shows atomic and ionic radii before and after ionization of the elements.
The answer is-
is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.
Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.
Determine the molecular geometry of
.
- Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
- According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
- Now, calculate the total number of valence electrons in
.

Valence electrons of S = 6
Valence electrons of F = 7
Thus, the valence electrons in
are-

- The Lewis structure of
is - (Image attached). - In the structure, the number of atoms bonded to central atom (S) = 6.
- Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
- Electronic geometry in case of 6 bond pairs is octahedral.
- Molecular geometry us also octahedral with bond angles 90°.
- Central atom is sp3d2 hybridised.
is a non-polar molecule.
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1-pentanol > 1-butanol > 1-chlorobutane > pentane
Explanation:
You my find in the attached picture the structures of the compounds, names and also the variation of their boiling points.
Alcohols have higher boiling points because they form hydrogen bonds between the molecules.
Learn more about:
boiling points in organic compounds
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The first thing we need to do here is to recognize the unit of molarity and the units of the given percentage of nitric acid.
Molarity is mol HNO3 / L of solution. This is our aim
The given percentage is 0.68 g HNO3/ g solution
multiplying this with density to convert g solution into mL solution and dividing with the molecular weight of HNO3 (63 g/mol) to convert g HNO3 to mol. Therefore we obtain
0.016 mol/ mL or 16.23 mol/ L (M)