What is the equation of the line that passes through the points (1, 1) and (5,5)?
1 answer:
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Answer:
Step-by-step explanation:
2y + 4 = 0 <em>subtract 4 from both sides</em>
2y = -4 <em>divide both sides by 2</em>
y = -2
The slope-intercept form of an equation of a line:
y = mx + b
m<em> - slope</em>
b<em> - y-intercept → (0, </em><em>b</em><em>)</em>
In the equation
y = -2
<em>slope: </em><em>m = 0</em>
<em>y-intercept: </em><em>b = -2 → (0, -2)</em>
<em />
<em>y = -2 - it's a horizontal line</em>
Answer:
(-6, -5)
Step-by-step explanation:
Reflection across the y-axis leaves the point on the same horizontal line, but with the sign of its x-coordinate changed.
(x, y) ⇒ (-x, y) . . . . . reflection across the y-axis
(6, -5) ⇒ (-6, -5)
The image point is (-6, -5).
