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ziro4ka [17]
3 years ago
13

Muons are elementary particles that are formed high in the atmosphere by the interactions of cosmic rays with atomic nuclei. Muo

ns are radioactive and have average lifetimes of about two-millionths of a second. Even though they travel at almost the speed of light, they have so far to travel through the atmosphere that very few should be detected at sea level - at least according to classical physics. Laboratory measurements, however, show that muons in great number do reach the earth's surface. What is the explanation?
Physics
1 answer:
uysha [10]3 years ago
5 0

Answer:

<em>Muons reach the earth in great amount due to the relativistic time dilation from an earthly frame of reference.</em>

Explanation:

Muons travel at exceedingly high speed; close to the speed of light. At this speed, relativistic effect starts to take effect. The effect of this is that, when viewed from an earthly reference frame, their short half life of about two-millionth of a second is dilated. The dilated time, due to relativistic effects on time for travelling at speed close to the speed of light, gives the muons an extended relative travel time before their complete decay. So <em>in reality, the muon do not have enough half-life to survive the distance from their point of production high up in the atmosphere to sea level, but relativistic effect due to their near-light speed, dilates their half-life; enough for them to be found in sufficient amount at sea level.  </em>

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Two forces with magnitudes of 6 pounds and 18 pounds are applied to an object. The magnitude of the resultant is 13 pounds. Find
Nikolay [14]

Answer: the angle between the resultant vector and the vector of the 18 pound is 28°

Explanation:

given that data in the question; as its interpreted in the diagram below;

from the cosine rule, we know that;

a² = b² + c² - 2bc  

so

(13)² = (6)² + (18)² - (2 × 6 × 18 ) cos∅

169 = 36 + 324 - 216cos∅

169 = 360 - 216cos∅

216cos∅ = 360 - 169

216cos∅ = 191

cos∅ = 0.8842

∅ = cos⁻¹ ( 0.8842 )

∅ = 27.8° ≈ 28°  {nearest whole number}

Therefore the angle between the resultant vector and the vector of the 18 pound is 28°

6 0
3 years ago
When two or more forces act together on an object what do they combine to form
Daniel [21]
Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.
7 0
3 years ago
A pressure cylinder has a diameter of 150-mm and has a 6-mm wall thickness. What pressure can this vessel carry if the maximum s
myrzilka [38]

Answer:

p = 8N/mm2

Explanation:

given data ;

diameter of cylinder =  150 mm

thickness of cylinder = 6 mm

maximum shear stress =  25 MPa

we know that

hoop stress is given as =\frac{pd}{2t}

axial stress is given as =\frac{pd}{4t}

maximum shear stress = (hoop stress - axial stress)/2

putting both stress value to get required pressure

25 = \frac{ \frac{pd}{2t} -\frac{pd}{4t}}{2}

25 = \frac{pd}{8t}

t = 6 mm

d = 150 mm

therefore we have pressure

p = 8N/mm2

7 0
3 years ago
Assuming a typical efficiency for energy use by the body, how many slices of pizza must you eat to walk for 2.5 h at a speed of
larisa86 [58]

Answer:

2.7 Pizzas.

Explanation:

The power required to walk through 5km in 1 hour is 380W.

A watt is basically Jules per second, then we need to standardized this measurement to second.

5km/hr is equal to,

\frac{5km}{hr}*\frac{1hr}{3600s}*\frac{1000m}{1km}=1.389m/s

Walking by 2.5 hours is equal to a distance of,

d=v*t=1.389*(2.5*3600) = 12500m

The total energy required then would be,

E = \frac{380J}{1.389m/s}(12500)=3.4199*10^6J

Then we know that one pizza slice gives 1260*10^3J of energy, the total pizza needed are,

\eta = \frac{3.4199*10^6}{1260*10^3} = 2.7142

<em>Then you need to buy 3 pizza.</em>

6 0
3 years ago
Gravitational potential energy is a form of potential energy
Gre4nikov [31]
True because it has "falling" ability
5 0
3 years ago
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