a loop of area 0.100 m^2 is oriented at a 15.5 degree angle to a 0.500 T magnetic field. it rotates until it is at a 45.0 degree
2 answers:
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Answer:
a) 141.6m
b) 8.4m/s
Explanation:
a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:
hence, the total distance is 141.6m
b) the mean velocity of the total trajectory is given by:
hence, the mean velocity is 8.4 m/s