Answer:
runway use is 3307.8 feet
Explanation:
given data
velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s
time = 28 seconds
weight = 28000 lbs
to find out
How many feet of runway was used
solution
we will use here first equation of motion for find acceleration
v = u + at ..............1
here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time
put here value in equation 1
72.016 = 0 + a(28)
a = 2.572 m/s²
and
now apply third equation of motion
s = ut + 0.5×a×t² .......................2
here s is distance and u is initial speed and t is time and a is acceleration
put here all value in equation 2
s = 0 + 0.5×2.572×28²
s = 1008.24 m = 3307.8 ft
so runway use is 3307.8 feet
Answer:
Ondas y sonido. Una onda es una perturbación que avanza o que se propaga en un medio material o incluso en el vacío. ... El sonido es un tipo de onda mecánica que se propaga únicamente en presencia de un medio material.
Explanation:
Answer:
constructive λ = 130 m
destructive λ = 260 m
Explanation:
a) the expression for constructive interference is that the difference in amino is equal to a multiple of the average wavelength
AQ - BQ = 2m λ/ 2 m = 0, 1, 2, ...
Where
AQ = 130 +50 = 180 m
BQ = 50 m
To find the smallest wavelength let's use m = 1
180 - 50 = 2 1 λ/ 2
λ = 130 m
b) for destructive interference
AQ –BQ = (2m + 1) λ/2
The smallest value is for m = 0
130 = λ / 2
λ = 260 m
That's true.
In fact, the resistance of a wire is given by:

where

is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
We see that the resistance of the wire is inversely proportional to the cross-sectional area: A. Therefore, the narrower the wire, the smaller A, the larger the resistance. But higher resistance means that the current flowing through the wire is lower, therefore the flow of electrons in the circuit is slower, and the initial sentence is true.