a loop of area 0.100 m^2 is oriented at a 15.5 degree angle to a 0.500 T magnetic field. it rotates until it is at a 45.0 degree
2 answers:
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The magnetic field strength is 9.47 ×10⁻⁴ T
The energy density at the center of the loop is 0.36 J/m³
<h3>Calculating Magnetic field strength & Energy density </h3>From the question, we are to find the magnetic field strength
The magnetic field strength of a loop can be calculated by using the formula,
Where B is the magnetic field strength
is the permeability of free space
is the current
and R is the radius
From the give information,
and
Putting the parameters into the formula, we get
Hence, the magnetic field strength is 9.47 ×10⁻⁴ T
Now, for the energy density
Energy density can be calculated by using the formula,
Where is the energy density
Then,
Hence, the energy density at the center of the loop is 0.36 J/m³
Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557
Answer:
Option B is the correct answer.
Explanation:
Period of a spring is given by the expression
Here, spring constant, k = 110 N/m
Mass = 0.41 kg
Substituting,
Option B is the correct answer.