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____ [38]
3 years ago
8

All but one statement applies to electromagnetic radiation

Physics
1 answer:
lina2011 [118]3 years ago
3 0
<span>D) Electromagnetic radiation travels in the form of longitudinal waves.</span>
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An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
Marysya12 [62]

When air is blown into the open pipe,

L = \frac{nλ}{2}

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=\frac{2L} {n}

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ=\frac{(2)*(6)}{4} =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= \frac{c}{λ}

⇒f=\frac{344}{3}

≈115 Hz

8 0
4 years ago
11.) An object that is NOT accelerating could be sitting still or:
Aleonysh [2.5K]

Answer:

moving slowly is the answer

4 0
3 years ago
Read 2 more answers
Your friend asks you for a glass of water and you bring her 5 milliliters of water. Is this more or less than what she was proba
Eddi Din [679]
Probably not what you were expecting... the average bottle of water is 24 ounces. 5 milliliters is about the amount of water in a spoon. Hope this helps!!!
3 0
3 years ago
The starter motor of a car engine draws an electric current of 20.0 A from the battery. The copper wire to the motor is 5.90 mm
insens350 [35]

Answer:

q = 13 C

Explanation:

Given that,

Electric current, I = 20 A

The starter motor runs for 0.65 s before the car engine starts up.

We need to find how much of electric charge passes through the starter motor. Let it is q.

Electric current = electric charge/time

I=\dfrac{q}{t}\\\\q=It\\\\q=20\ A\times 0.65\ s\\\\q=13\ C

So, 13 C of electric charge passes through the starter motor.

6 0
3 years ago
What is the sprinters output at 2.0 s, 4.0 s and 6.0 s?
kari74 [83]

A 59 kg sprinter, starting from rest, runs 47 m in 7.0 s at constant acceleration.?  

What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s?  

Instantaneous Power is the force times velocity  

P = Fv  

Because the acceleration is constant, the force will be constant as well  

F = ma  

P = mav  

for constant acceleration, the velocity at each time is found using  

v = at  

P = ma(at) = ma²t  

find the acceleration using kinematic equation  

s = ½at²  

a = 2s/t²  

a = 2(47) / 7.0²  

a = 1.918 m/s²  

P(2.0) = 59(1.918²)2.0 = 434.25 W = 0.43 kW  

P(4.0) = 59(1.918²)4.0 = 868.51 W = 0.87 kW  

P(6.0) = 59(1.918²)6.0 = 1302.76 W = 1.3 kW  

I hope this helped.  


5 0
4 years ago
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