In order of increasing frequency: Radio, Microwaves, Infrared, Visible light, Ultra-violet, X-rays, Gamma rays. To remember this try:
Rabbits
Mates
In
Very
Unusual
e(X)pensive
Gardens
Answer:
3.73 * 10^16 photons/sec
Explanation:
power supply = 3.0 V
Emits 440 nm blue light
current in LED = 11 mA
efficiency of LED = 51%
<u>Calculate the number of photons per second the LED will emit </u>
first step : calculate the energy of the Photon
E = hc / λ
=( 6.62 * 10^-34 * 3 * 10^8 ) / 440 * 10^-9
= 0.0451 * 10^-17 J
Next :
Number of Photon =( power supply * efficiency * current ) / energy of photon
= ( 3 * 0.51 * 11 * 10^-3 ) / 0.0451 * 10^-17
= 3.73 * 10^16 photons/sec
The change in energy after the collision is <u>0.5</u>
<u />
<h3>What is change in energy?</h3>
This refers to the difference in the energy where energy is the capacity to do work. There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.
The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy
<h3>solving for the change in energy as a result of the collision</h3>
where mass of particle mp = 4 kg
mass of object mb = 6 kg
force constant of spring k = 100 N/m
amplitude A = 2 m
kinetic energy = 1/2 mv^2
initial velocity u = Aω
ω = sqrt ( 100/ 4 )
u = 2 sqrt ( 100/ 4 )
u = 10m/s
final velocity v = 5 m/s
change in energy
= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2
= 0.5
Read more on change in energy here: brainly.com/question/26066414
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Answer:
The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.
Explanation:
We can describe single slit diffraction phenomenon with the equation:
(1)
with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum (
) are small compared to the distance between the screen and the slit (x), we can approximate
, using this on (1):

solving for y

Note that
is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find
,
add them and divide by two:




