If you are convicted of a dui for a second time in five years, your license may be revoked for up to (2) years
Answer:
note:
<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>
The modulus of elasticity is 28.6 X 10³ ksi
<u>Explanation:</u>
Given -
Length, l = 5in
Force, P = 8000lb
Area, A = 0.7in²
δ = 0.002in
Modulus of elasticity, E = ?
We know,
Modulus of elasticity, E = σ / ε
Where,
σ is normal stress
ε is normal strain
Normal stress can be calculated as:
σ = P/A
Where,
P is the force applied
A is the area of cross-section
By plugging in the values, we get
σ = 
σ = 11.43ksi
To calculate the normal strain we use the formula,
ε = δ / L
By plugging in the values we get,
ε = 
ε = 0.0004 in/in
Therefore, modulus of elasticity would be:

Thus, modulus of elasticity is 28.6 X 10³ ksi
Answer:
3270 N/m^2
Explanation:
we can calculate the pressure difference between the bottom and surface of the tank by applying the equation for the net vertical pressure
Py = - Ph ( g ± a )
for a downward movement
Py = - Ph ( g - a ) ------ ( 1 )
From the above data given will be
p = 1000 kg/m^3, h = 2/3 * 0.5 = 0.33 m , a =2g , g = 9.81
input values into equation 1 becomes
Py = -Ph ( g - 2g ) = Phg ------ ( 3 )
Py = 1000 * 0.33 * 9.81
= 3270 N/m^2