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Mrac [35]
2 years ago
10

3) While flying horizontally in an airplane, you notice that a string dangling from the overhead

Physics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer:

A

Explanation:

the string would be dangling backwards because you are moving forward it would be putting backward force on the string

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A quantity of gasoline injected into car engine has a potential energy of 100J. All of this energy is not converted into useable
neonofarm [45]

Answer:because some energy are lost due to friction

Explanation:some energy are lost due to friction

5 0
3 years ago
What does the magnitude of centripetal acceleration depend on ?
MariettaO [177]

Explanation:

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 .

3 0
3 years ago
A toy car moves 8 min 4 s at the constant velocity. What is the car's velocity?
Schach [20]

Explanation:

<u>Formula:</u>

velocity = (d \div t)

<u>d = distance given</u>

<u>t</u><u> </u><u>=</u><u> </u><u>the amount of time </u><u>given</u>

<u>Substitute the given values into the formula for velocity</u><u>:</u>

v = 8 \div 4

velocity is shortened for v.

8 (distance) divided by 4 (time) equals the velocity.

<u>Solve:</u>

2 = 8 \div 4

The velocity of the toy car equals: B. 2 m/s.

6 0
2 years ago
Take a long look at the moon. What evidence do you see that indicates that it is NOT tectonically active Explain.
eduard
<span>Without plate tectonics, new mountain belts could not form. Earth would be a Waterworld with occasional shield volcanoes emerging briefly above the waves. If regular catastrophic convective overturn occurred, as on Venus, life would have a precarious foothold indeed.

</span>
4 0
3 years ago
The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v
Mademuasel [1]

Answer:

a = -04978 m / s²

Explanation:

For this exercise we can use the kinematics equations, as the initial speed, distance and time indicate, we can use

        x = x₀ + v₀ t + 1 /2 a  t²

       ½ a t² = x-x₀ - v₀ t

       a = (x-x₀ - v₀ t) 2 / t²

let's reduce the magnitudes to the SI system

     x₀ = 1000 mm = 1 m

     x  = 5000mm = 5m

let's calculate

     a = (5 - 1 - 15 60) 2/60²

     a = -04978 m / s²

negative sign indicates that braking is related

7 0
2 years ago
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