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lawyer [7]
3 years ago
5

An account voltage is connected to an RLC series circuit of resistance 5ohms, inductance 3mH, and a capacitor of 0.05f. calculat

e the resonance frequency
Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

12.99 Hz

Explanation:

Resonance is said to occur in an RLC circuit when maximum current is obtained from the circuit. Hence at resonance; XL=XC and Z=R.

XL= inductive reactance, XC= capacitive reactance, Z= impedance, R= resistance

The resonance frequency is given by;

fo= 1/2π√LC

L= 3×10^-3 H

C= 0.05 F

π= 3.142

Substituting values;

fo= 1/2×3.142√3×10^-3 × 0.05

fo= 12.99 Hz

Therefore the resonance frequency of the RLC circuit is 12.99 Hz

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Answer:

The can mass is 0,00359 kg or 3,59 g

Explanation:

1. Relevant Data:

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Cylinder volume equation is:

V=\frac{1}{4}\pi  d^{2}h

Considering that the can is an object with a hole inside, then we need to estimate the real volume of the sheet of steel.

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Then, we could say that dD=0.013 cm

Replacing the values of d, h and dD, we obtain:

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dV=0,4492 cm^3

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5 0
4 years ago
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emmainna [20.7K]

Answer:

zero

Explanation:

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