Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.
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Answer:
2.6 m
Explanation:
The work done by the bird is given by

where
F is the force exerted
d is the distance covered
In this problem, we know:
is the work
is the force
Solving the equation for d, we find the distance covered by the bird:

a is the correct
Explanation:
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Answer:
a) 0.002 cm³
b) 0.005 cm³
Explanation:
density d = 19 kg/cm³
Given mass m, find volume V
The definition of density is
d = m/V
so V = m/d
a) m = 38 g = 0.038 kg
so V = 0.038/19 = 0.002 cm³
b) m = 0.095 kg
V = 0.095/19 = 0.005 cm³