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kiruha [24]
2 years ago
8

Wile E. Coyote is holding a "HEAVY DUTY ACME™ ANVIL" on a cliff that is 40.0 meters high. The Roadrunner (beep-beep), who is 1.0

meter tall, is running on a road toward the cliff at a constant velocity of 10.0 m/s. Wile E. Coyote wants to drop the anvil on the Roadrunner's head. How far away should the Roadrunner be when Wile E. drops the anvil?​
Physics
1 answer:
Mariana [72]2 years ago
3 0

Answer:

53.8

Explanation: I plugged it on the formula

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At a construction site, the site manager notices that a crane takes 20 seconds to lift a 500kg steel beam up to a height of 15 m
posledela
The work done is equal to the change in potential energy which is:
P.E = mgh
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5 0
4 years ago
An electric field around two charged objects is shown.
mamaluj [8]

Answer: D

<u></u>

X: positive

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Explanation:

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3 years ago
A 70.0-kg ice hockey goalie, originally at rest, catches a 0.150-kg hockey puck slapped at him at a velocity of 35.0 m/s. Suppos
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Answer:

v₂=- 34 .85 m/s

v₁=0.14 m/s

Explanation:

Given that

m₁=70 kg ,u₁=0 m/s

m₂=0.15 kg ,u₂=35 m/s

Given that collision is elastic .We know that for elastic  collision

Lets take their final speed is v₁ and v₂

From momentum conservation

m₁u₁+m₂u₂=m₁v₁+m₂v₂

70 x 0+ 0.15 x 35 = 70 x v₁ + 0.15 x v₂

70 x v₁ + 0.15 x v₂=5.25                   --------1

v₂-v₁=u₁-u₂            ( e= 1)

v₂-v₁ = -35        --------2

By solving above equations

v₂=- 34 .85 m/s

v₁=0.14 m/s

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3 years ago
If Phoenix, Arizona, experiences a cool, wet day in June, does that mean the regions climate is changing?
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