Explanation:
<h2>
For Copper</h2>
dH copper = mCdT copper
<em>(Specific Heat of copper=0.385 J/g C )
</em>
dH = 500 g (0.385 J/g C) (78 C rise)
dH = 15,015 Joules
<h2>
For Water</h2>
dH water = m C dT water
<em>(Specific Heat of copper=</em>4.184 J/g-C<em>)
</em>
<em />
dH = 400 g (4.184 J/g-C) (78 C rise)
dH = 130,540 Joules
total heat = 15,015 + 130,540 = 145,555 Joules
<h2>
Percentage for Water </h2>
(130,540 Joules / 145,555 Joules) x 100 = 89.7 %
If we consider that we have 3 Significant Figures,
then, the answers become
,
15.0 KJ must be added for Copper
130.5 KJ must be added for Water
and the total of 145 KJ must be added in the kettle with the water
89.7 % of heat goes to the Water
