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777dan777 [17]
3 years ago
11

Calculate a. The heat that must be supplied to a 500.0 g copper kettle containing 400.0 g of water to raise its temperature from

22.0°C to the boiling point of water, 100.0°C. b. What percentage of the heat is used to raise the temperature of the water?
Physics
1 answer:
uysha [10]3 years ago
7 0

Explanation:

<h2>For Copper</h2>

dH copper = mCdT copper

<em>(Specific Heat of copper=0.385 J/g C )   </em>

dH = 500 g (0.385 J/g C) (78 C rise)

dH = 15,015 Joules

<h2> For Water</h2>

dH water =  m C dT water

<em>(Specific Heat of copper=</em>4.184 J/g-C<em>)   </em>

<em />

dH = 400 g (4.184 J/g-C) (78 C rise)

dH = 130,540 Joules

total heat = 15,015 + 130,540 = 145,555 Joules

<h2>Percentage for Water  </h2>

(130,540 Joules  / 145,555 Joules) x 100 = 89.7 %

If we consider that we have 3 Significant Figures,

then, the answers become ,

15.0 KJ must be added for Copper

130.5 KJ must be added for Water

and the total of 145 KJ must be added in the kettle with the water

89.7 %  of heat goes to the Water

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