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Strike441 [17]
3 years ago
9

A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of

a gazelle assumes an acceleration of 4.2 m/s2 for 6.5 s , after which the gazelle continues at a steady speed.
Physics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

The gazelles top speed is 27.3 m/s.

Explanation:

Given that,

Acceleration = 4.2 m/s²

Time = 6.5 s

Suppose we need to find the gazelles top speed

The speed is equal to the product of acceleration and time.

We need to calculate the gazelles top speed

Using formula of speed

v=at

Where, v = speed

a = acceleration

t = time

Put the value into the formula

v=4.2\times6.5

v=27.3\ m/s

Hence, The gazelles top speed is 27.3 m/s.

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If your parasympathetic nervous system was activated what might you be doing?
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Explain the relationship between mass and acceleration
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3 years ago
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ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. You travel 20.0 mph f
timurjin [86]
The actual answer is 165 miles, but using significant figure rules the answer is 200. This is because the sig fig rules are as follows ...
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2. Any zeros between two significant digits are significant.
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So the zeroes in a number like 20 or 23,000 are NOT significant. When you add numbers you must find the addend with the lowest amount of significant figures and round the answer to that. In this case most of the addends only have one sig fig, so you round 165 to 200 to make it only have one sig fig.
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4 years ago
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Suppose a 350-g kookaburra (a large kingfisher bird) picks up a 75-g snake and raises it 2.5 m from the ground to a branch. (a)
mafiozo [28]

(a) The work done by the bird to raise the snake on the branch is equal to the product between the weight of the snake and the height of the branch above the ground:

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where m=75 g=0.075 kg is the mass of the snake and h=2.5 m is the height of the branch with respect to the ground. Substituting numbers into the equation, we find

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(b) The work the bird did to raise its own centre of mass from the ground to the branch is equal to the product between the bird's weight and the height of the branch:

W_2 = mgh

where m=350 g=0.35 kg is the mass of the bird. Substituting numbers into the equation, we find

W_2 = (0.35 kg)(9.81 m/s^2)(2.5 m)=8.58 J

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3 years ago
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