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larisa [96]
2 years ago
9

How many Fahrenheit degrees are needed to equal one Celsius (or Kelvin) degree?

Physics
1 answer:
Nat2105 [25]2 years ago
3 0
One Celsius degree is the same size as one Kelvin. Each of them is the size of 1.8 Fahrenheit degrees.
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What is the force of an object with a mass of 30 kg that is free falling?
disa [49]

Answer:

F = 294.3 [N]

Explanation:

To solve this problem we must use Newton's second law which tells us that force is equal to the product of mass by acceleration. It is this particular case the acceleration is due to the gravitational acceleration since the body is in free fall.

Therefore we have:

F = m*g

where:

F  = force [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s^2]

F = 30*9.81

F = 294.3 [N]

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3 years ago
What are the characteristics of a blackbody radiator? Give an example.
mihalych1998 [28]

Answer:

A blackbody, or Planckian radiator, is a cavity within a heated material from which heat cannot escape. No matter what the material, the walls of the cavity exhibit a characteristic spectral emission, which is a function of its temperature.

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2 years ago
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sergiy2304 [10]

Answer:

B, A, C

Explanation:

3 0
3 years ago
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laila [671]

3b. No

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3 years ago
You go to the hardware store to buy a new 50 ft garden hose. You find you can choose between hoses of ½ inch and 5/8 inch inner
omeli [17]

To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,

Q = V*A

Where,

A= Cross-sectional Area

V = Velocity

The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,

Q_1 = Q_2

V_1A_1=V_2A_2

Our values are given as,

A_1=\frac{1}{2}^2*\pi=0.785 in^2

A_2=\frac{5}{8}^2*\pi=1.227 in^2

Re-arrange the equation to find the first ratio of rates we have:

\frac{V_1}{V_2}=\frac{A_2}{A_1}

\frac{V_1}{V_2}=\frac{1.227}{0.785}

\frac{V_1}{V_2}=1.56

The second ratio of rates is

\frac{V2}{V1}=\frac{A_1}{A2}

\frac{V2}{V1}=\frac{0.785}{1.227}

\frac{V2}{V1}=0.640

3 0
3 years ago
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