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larisa [96]
3 years ago
9

How many Fahrenheit degrees are needed to equal one Celsius (or Kelvin) degree?

Physics
1 answer:
Nat2105 [25]3 years ago
3 0
One Celsius degree is the same size as one Kelvin. Each of them is the size of 1.8 Fahrenheit degrees.
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How do you calculate resistance with coulombs, time and J's?
Mars2501 [29]
Hey user


The energy E in joules (J) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C):

E(J) = V(V) ×<span> Q</span>(C)

So

joule = volt × coulomb

or

J = V × C

Example

What is the energy in joules that is consumed in an electrical circuit with voltage supply of 15V and charge flow of 4 coulombs?

E = 15V × 4C = 60J

4 0
4 years ago
A runner can run a 400.0 meter lap in 50.0 seconds.   He finishes at the same spot as he began.  What is his average velocity?
cestrela7 [59]
8 meters per second. To find velocity is to divide distance by total time. so 400/50.
8 0
4 years ago
Read 2 more answers
A positively charged particle is in the center of a parallel plate capacitor that has charge +/- Q on it's plates. Suppose the d
ivolga24 [154]

Answer:

the force remains constant if the charge does not change

Explanation:

In a capacitor the capacitance is given by

           C = ε₀ A / d

Where ε₀ is the permissiveness of emptiness, A is about the plates and d the distance between them.

The charge on the capacitor is given by the ratio

            Q = C ΔV

Let's apply these expressions to our problem, if the load remains constant

            C = Q / ΔV = ε₀ A / d

            ΔV / d = Q / ε₀ A

If the distance increases the capacitance should decrease, therefore if the charge is a constant the voltaje difference must increase

Now we can analyze the force on the test charge in the center of the capacitor

               ΔV = E d

               E= ΔV/d

               F = q E

              F = q ΔV / d

 Let's replace

          F = q Q /ε₀ A

From this expression we see that the force is constant since the voltage increase is compensated by increasing the distance, therefore the correct answer is that the force remains constant if the charge does not change

8 0
3 years ago
A 1.89 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 N
Maksim231197 [3]

Answer:

Magnitude F(t)=26.6 N

Direction: -x

Explanation:

Given data

Spring constant K=4.77 N/m

Mass m=1.89 kg

Displace A=5.56m

Time t=3.96s

To find

Magnitude of force F

Solution

The angular frequency is given as

w=\sqrt{\frac{K}{m} } \\w=\sqrt{\frac{4.77N/m}{1.89kg} }\\w=1.59rad/s

Force on object is

F(t)=-mAw^{2}Cos(wt)

Substitute given values

So

F(t)=-(1.89kg)(5.56m)(1.59rad/s)^{2}Cos(1.59*3.96)\\F(t)=-26.6N

So

Magnitude F(t)=26.6 N

Direction: -x

4 0
3 years ago
Why do you seem to "fly forward" when you slam on the brakes of a car? what forces are involved?
san4es73 [151]
Its because of inertia.
due to inertia u tries to be in the same state of motion, in this case u have a tendency to remain in forward motion as the car suddenly tries to stop, so u move forward.
all the best
8 0
3 years ago
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