Answer:

Explanation:
Given:
- file size to be transmitted,

- transmission rate of data,

- propagation speed,

- distance of data transfer,

<u>Now the delay in data transfer from source to destination for each 10 Mb:</u>



<u>Now this time is taken for each 10 Mb of data transfer and we have 30 Mb to transfer:</u>
So,



Answer:
<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)
Explanation:
<u>Average Acceleration</u>
The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

Where vf is the final speed, vo is the initial speed and t is the time.
The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

The average acceleration is 0.5 cm/s^2
A) Correct. The average acceleration is 0.5 cm/s^2
B) Incorrect. The average acceleration is 0.5 cm/s^2
C) Incorrect. The average acceleration is 0.5 cm/s^2
D) Incorrect. The average acceleration is 0.5 cm/s^2
Find and Replace dialog box is probably the most useful.
Warm air expands and rises up while cold air condenses and sinks.
Hopefully I could help :)
The amount of work done on the weights would be approximately 15.0 Kg of work