Answer: 3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)
Explanation:
The question requires us to write down the net ionic equation for the precipitation of silver phosphate from aqueous solution:________
Note that we we told to:
(Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)
Answer:
From the solubility rule,
Phosphate (PO₄³⁻) and Carbonates are insoluble except for NH₄⁺ and Group1A compounds.
According to the solubility rule, the precipitation of silver phosphates and that of the net ionic equations is given thus;
3AgNO³ (aq) + K₃PO₄ (aq) → Ag₃PO₄ (s) + 3KNO₃ (aq)
while the Net ionic equation is given;
3Ag⁺ (aq) + PO₄³⁻ (aq) → Ag₃PO₄ (s)
cheers i hope this helped !!
