Explanation:
General electronic configuration for the given groups are as follows.
For 4A(14) : 
This means that there are 4 unpaired electrons in group 4A(14).
For 7A(17) :
So, there are 7 unpaired electrons present in group 7A(17).
For 1A(1) : 
Hence, there is only one unpaired electron present in group 1A(1).
For 6A(16) :
So, there are 6 unpaired electrons present in group 6A(16).
Answer:
2Ag + CaCl2
Explanation:
https://en.intl.chemicalaid.com/tools/equationbalancer.php?equation=Ca+%2B+AgCl+%3D+Ag+%2B+CaCl2 use that website for chemistry
Answer:
23 kPA
Explanation:
95kPa = 24kPA (CO2) + 48 kPa (N) + x kPa (O)
24kPA(CO2)+ 48kPA (N) = 72 kPA
95kPA - 72kPA= 23kPA (O)