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3 years ago

9

A physician has a patient that he believes has had foul play. What type of autopsy would the physician request?

1 answer:

BabaBlast [244]3 years ago

4 0

<span>Medical- legal autopsy would help determine the cause of death and confirm or reject the doctors suspicions. This is also more broadly defined as a forensic autopsy as well. This type covers death by suspicion, death without a doctor present, and also death while in surgery.</span>

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Approximate the field by treating the disk as a +6.1 C point charge at a distance of 21 cm Answer in units of N/C.

DaniilM [7]

Answer:

Electric field, $E=1.24\times 10^{12}\ N/C$

Explanation:

It is given that,

Charge, Q = +6.1 C

Distance, r = 21 cm = 0.21 m

We need to find the electric field. It is given by :

$E=k\dfrac{Q}{r^2}$

$E=9\times 10^9\times \dfrac{6.1}{(0.21)^2}$

$E=1.24\times 10^{12}\ N/C$

So, the electric field at this distance is $1.24\times 10^{12}\ N/C$ . Hence, this is the required solution.

7 0

2 years ago

A camera flash, which throws a parallel beam of light, has a mirror behind the light bulb. What kind of mirror is it likely to b

WINSTONCH [101]

For Plato, the correct answer is Concave mirror :)

3 0

3 years ago

Read 2 more answers

Which of the following statements about the resistsance of a wire is correct? Select THREE answers.

viva [34]

Answer:

Its a

Explanation:

4 0

2 years ago

Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the

Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

$m=180 kg$ the mass of the raft

$F=75 N$ the force applied by Sawyer

$V=2 m/s$ the raft's final speed

$V_{o}=0 m/s$ the raft's initial speed (assuming it starts from rest)

We have to find the time $t$

Well, according to Newton's second law of motion we have:

$F=m.a$ (1)

Where $a$ is the acceleration, which can be expressed as:

$a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}}$ (2)

Substituting (2) in (1):

$F=m\frac{V-V_{o}}{t-t_{o}}$ (3)

Where $t_{o}=0$

Isolating $t$ from (3):

$t=\frac{m(V-V_{o})}{F}$ (4)

$t=\frac{180 kg(2 m/s-0 m/s)}{75 N}$

Finally:

$t=4.8 s$

6 0

2 years ago

What does the area under the velocity-time graph represent.

V125BC [204]

Answer:

The distance traveled!

Explanation:

This is a velocity time graph of an object moving in a straight line due North.

8 0

2 years ago