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2 years ago

The sizes of most of the cells our bodies are about A.1micrometer

2 answers:

8 0

I would think it would be A but the sizes of cells varies between 1-100 micrometer

hope this helps

Have a happy holidays:)

Alekssandra [29.7K]2 years ago

5 0

Answer:

1Mm

Explanation:

i think this one. so it is wrong then also dont be angry with me because iam trying to help u

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1. Define cellular respiration, and state where it takes place.

larisa [96]

Answer:

1. Cellular respiration is the process in which cells break down glucose, release the stored energy, and use it to make ATP. The process begins in the cytoplasm and is completed in a mitochondrion. Cellular respiration occurs in three stages: glycolysis, the Krebs cycle, and electron transport.

2. How much ATP is produced in all three stages combined? Glycolysis produces 2 ATP molecules, and the Krebs cycle produces 2 more. Electron transport from the molecules of NADH and FADH2 made from glycolysis, the transformation of pyruvate, and the Krebs cycle creates as many as 32 more ATP molecules.

3. Photosynthesis converts carbon dioxide and water into oxygen and glucose. ... Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

4. Aerobic respiration takes place in presence of oxygen; whereas anaerobic respiration takes place in absence of oxygen. Carbon dioxide and water are the end products of aerobic respiration, while alcohol is the end product of anaerobic respiration. Aerobic respiration releases more energy than anaerobic respiration.

7 0

3 years ago

The drawing shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel a

Pavel [41]

Answer:

$F=27.39N$

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

Σ $T=T_{N}+T_{f}+T_{W}$

Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

$T_{N}=0$

The perpendicular lever arm for the F force is R-h

$T_{f}=F*(r-h)$

And the T of gravity according to the image

$T_{W}=W*(\sqrt{r^2-(r-h)^2}$

Σ $T=0$

$T_{N}+T_{f}+T_{W}=0$

$F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0$

$F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}$

$F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}$

$F=27.39N$

4 0

3 years ago

A ductile metal wire has resistance R. What will be the resistance of this wire in terms of R if it is stretched to three times

Ira Lisetskai [31]

Answer:

Explanation:

We know that the resistance is $R=\rho *\frac{L}{A}$ .

If we stretch the wire to a new length L2 = 3L, the cross-sectional area will also change. If the cross-sectional area doesn't change throughout the wire, we can say that:

Volume = L*A = 3L * A2 being A2 the new area after stretching the wire.

Since the volume remains the same we conclude that A2 = A/3

With this information, we calculate the new resistance:

$R2=\rho *\frac{L2}{A2}=\rho *\frac{3*L}{A/3}=\rho * 9 * \frac{L}{A}$

Since $R=\rho *\frac{L}{A}$ , and by simple inspection of the previous equation, we get:

6 0

3 years ago

A ray of yellow light ( f8= 5.09 × 1014 Hz) travels at a speed of 2.04×10 meters per second in

Gala2k [10]

The complete question in the attached figure
Let
c ------------------- > is the speed of light
v ------------------- > is the speed in medium
n ------------------- > is the refractive index of medium
we know that
c/v = n
n = (3 x 10^8)/(2.04 x 10^8) = 1.47

1.47 is the refractive index of glycerol.
therefore

the answer is (4) glycerol

5 0

3 years ago

Read 2 more answers

A trip is taken that passes through the following points in order

AURORKA [14]

Answer:

15? I actually don't know

3 0

3 years ago