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2 years ago

The sizes of most of the cells our bodies are about A.1micrometer

2 answers:

8 0

I would think it would be A but the sizes of cells varies between 1-100 micrometer

hope this helps

Have a happy holidays:)

Alekssandra [29.7K]2 years ago

5 0

Answer:

1Mm

Explanation:

i think this one. so it is wrong then also dont be angry with me because iam trying to help u

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What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

nadezda [96]

<h3><u>Given</u> :</h3>

Current flow light bulb = 2.5 $\sf{A}$

Resistance of light bulb = 3.6Ω

We have to find voltage of battery $.$

<h3><u>Solution</u> :</h3>

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

➝ <u>V = I × R</u>

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

⇒ <u>V = 9 volt</u>

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2 years ago

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Explanation:

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2 years ago

As part of a daring rescue attempt, the Millennium Eagle coasts between a pair of twin asteroids, as shown in the figure below w

Luden [163]

The correct answer is 3 wiv 2=6

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2 years ago

Compare the mass on Neptune (68.11) to the weight on Neptune (905.863). What is the difference? Why is there a difference?

Alchen [17]

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2 years ago

A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal

slamgirl [31]

Answer:

18.89cm

Explanation:

As we know that the person is standing 5m in front of the camera

$d_0=5m=500cm$

The focal length of the lens =50cm

f=50 cm

By Lens formula we have:

$\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm$

By the formula of magnification

$\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm$

The height of the image formed is 18.89cm.

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2 years ago