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Mars2501 [29]
3 years ago
13

16.01 g of sulfur trioxide was decomposed into 6.41 g of sulfur and 9.60 g of oxygen. How many grams of sulfur trioxide would be

needed to produce 28.80 g of oxygen?
Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

48 grams of sulfur trioxide.

Explanation:

The equation of reaction involves the decomposition of 2 moles of sulfur trioxide (SO3) to produce 2 moles of atomic sulfur (S) and 3 moles of molecular oxygen (O2).

From the equation of reaction above,

3 moles of molecular oxygen (96 g) was produced from 2 moles of sulfur trioxide (160 g)

Mass of sulfur trioxide needed to produce 28.8 g of oxygen = 28.8×160/96 = 48 grams

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How many moles are there in 3.9 grams of potassium
polet [3.4K]

Answer:0.025576559594663 mole.

Explanation:

3 0
3 years ago
Give the oxidation state of sulfur in (d) H₂S ;
earnstyle [38]

The correct answer is -2 oxidation state.

Assume that the oxidation number of the sulfur atom in H2S S is x.Now, 2+x=0 ⇒ x=−2. As a result, the oxidation number of sulfur in H2S is -2. Various organosulfur compounds are produced by combining Hydrogen sulfide with sulfur. Sewer gas, swamp gas, stink damp, and sour damp all include Hydrogen sulphide, an invisible gas. It smells strongly of eggs, even in small amounts. It is extremely flammable and poisonous. While drilling for and producing crude oil and natural gas, gases like Hydrogen sulfide (H2S) are regularly found.

learn more about Hydrogen sulfide here:

brainly.com/question/14400769 

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5 0
2 years ago
A balloon filled with helium has a volume of 6.9 L. What is the mass, in grams, of helium in the balloon?
balandron [24]

Answer : The mass of helium gas in the balloon is, 1.23 grams.

Explanation : Given,

Volume of helium gas = 6.9 L

First we have to calculate moles of helium gas at STP.

As we know that, 1 mole of substance occupy 22.4 L volume of gas.

As, 22.4 L volume of helium gas present in 1 mole of helium

So, 6.9 L volume of helium gas present in \frac{6.9L}{22.4L}\times 1mole=0.308mole of helium

Now we have to calculate the mass of helium gas.

\text{Mass of He gas}=\text{Moles of He gas}\times \text{Molar mass of He gas}

Molar mass of He gas = 4 g/mol

\text{Mass of He gas}=0.308mol\times 4g/mol=1.23g

Thus, the mass of helium gas in the balloon is, 1.23 grams.

6 0
3 years ago
Question 1 (1 point)<br> How many significant figures are in the number 2,000 ?
Flauer [41]

Answer:

One  

Explanation:

Trailing zeros in a number are not significant unless they follow a decimal point.

If you want to specify a different number of significant figures, you can use a decimal point.

For example,

     2.0 × 10³ = two significant figures

  2.00 × 10³ = three significant figures

2.000 × 10³ = four significant figure

        2000. = four significant figures

5 0
3 years ago
How much energy is released when 65.8 g of water freezes
Delvig [45]

The amount of energy released is calculated by the product of heat of fusion and mass. The formula of amount energy released is given by: q= L\times m                (1)

Here,  

q is amount of energy released L is heat of fusion (334 J/g) m is mass of water Put all the given values in equation (1)

q= 334 J/g \times 65.8 g

q= 21977.2 Joules ≅ 21977 Joules

q= 21977 Joules

Thus, amount of energy released is 21977 Joules


6 0
3 years ago
Read 2 more answers
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