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Mars2501 [29]
3 years ago
13

16.01 g of sulfur trioxide was decomposed into 6.41 g of sulfur and 9.60 g of oxygen. How many grams of sulfur trioxide would be

needed to produce 28.80 g of oxygen?
Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

48 grams of sulfur trioxide.

Explanation:

The equation of reaction involves the decomposition of 2 moles of sulfur trioxide (SO3) to produce 2 moles of atomic sulfur (S) and 3 moles of molecular oxygen (O2).

From the equation of reaction above,

3 moles of molecular oxygen (96 g) was produced from 2 moles of sulfur trioxide (160 g)

Mass of sulfur trioxide needed to produce 28.8 g of oxygen = 28.8×160/96 = 48 grams

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Lubov Fominskaja [6]
The answer is +1! Have a great day!
6 0
3 years ago
Which phrase change is an endothermic change? (1 point)
Vadim26 [7]
An Endothermic change is a process in which there is absorption of energy.
-Condensation is the transformation from a gas to a liquid. So the water molecules releases energy while condensing, so condensation is exothermic (opposite of endothermic, it's the release of energy)
-Vaporization is the transformation from a liquid to a gas. When you heat water to evaporate it, you're giving energy to the water molecules. And when they absorb this energy, they transform to a gas. Which means that Vaporization is endothermic.
-Deposition is the transformation from gas directly to solid without passing by the liquid phase. Same as the condensation, but the water molecules release even more energy to directly become Solid. So deposition is exothermic.
-Freezing is the transformation from a liquid to a solid. During this phase, water molecules releases energy to its surrounding. So freezing is exothermic.

We can conclude that Vaporization is endothermic, because it's absorbing energy to transform from liquid to gas, while condensation, deposition and freezing are exothermic because they release energy to transform.

Hope this Helps! :)
5 0
4 years ago
Write the ions present in solution of k2co3. express your answers as chemical formulas separated by a comma. identify all of the
GarryVolchara [31]

Answer : The ions present in the solution of K_2CO_3 are K^+ and CO^{2-}_3 in aqueous state.

Explanation :

When K_2CO_3 is in aqueous solution then they dissociates into their ions.

The reaction in aqueous medium is,

K_2CO_3(aq)\rightarrow 2K^+(aq)+CO^{2-}_3(aq)

The charge on potassium ion is +1 and on carbonate ion is -2. To neutralize the charge on carbonate ion, two potassium ion must be used.

Therefore, the ions present in solution of K_2CO_3 are K^+ and [tex]CO^{2-}_3[tex] in aqueous state.

8 0
3 years ago
Read 2 more answers
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 162. kJ during a certain chemical reaction, w
Lerok [7]

Explanation:

It is given that the energy change is -162 kJ and work done is -194 kJ. As we know that formula for change in enthalpy is as follows.

                           dH = dE + W

where,     dH = change in enthalpy

                dE = change in energy

                W = work done

Therefore, the change in enthalpy will be as follows.

                      dH = dE + W

                            = -162 kJ + (-194 kJ)

                            = -356 kJ

As the negative sign indicates heat is being released. Therefore, the reaction is exothermic in nature.

Thus, we can conclude that the change in energy of the gas mixture during the reaction is -356 kJ.

3 0
3 years ago
Question14 of 20If 5.15 g FeCl3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molar concentrati
Serhud [2]

Answer: 0.635 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{5.15g}{162.4g/mol}=0.0317moles  

V_s = volume of solution  = 150 ml

Molarity=\frac{0.0317\times 1000}{150ml}=0.2114M

FeCl_3\rightarrow Fe^{3+}+3Cl^-

as 1 mole of FeCl_3 gives 3 moles of Cl^- ions

Thus molarity of Cl^- = 3\times 0.2114=0.635M

Molarity of Cl^- = 0.635 M

8 0
3 years ago
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