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Mars2501 [29]
3 years ago
13

16.01 g of sulfur trioxide was decomposed into 6.41 g of sulfur and 9.60 g of oxygen. How many grams of sulfur trioxide would be

needed to produce 28.80 g of oxygen?
Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

48 grams of sulfur trioxide.

Explanation:

The equation of reaction involves the decomposition of 2 moles of sulfur trioxide (SO3) to produce 2 moles of atomic sulfur (S) and 3 moles of molecular oxygen (O2).

From the equation of reaction above,

3 moles of molecular oxygen (96 g) was produced from 2 moles of sulfur trioxide (160 g)

Mass of sulfur trioxide needed to produce 28.8 g of oxygen = 28.8×160/96 = 48 grams

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<h3>Answer:</h3>

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<h3>Explanation:</h3>

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