The equation of reaction involves the decomposition of 2 moles of sulfur trioxide (SO3) to produce 2 moles of atomic sulfur (S) and 3 moles of molecular oxygen (O2).
From the equation of reaction above,
3 moles of molecular oxygen (96 g) was produced from 2 moles of sulfur trioxide (160 g)
Mass of sulfur trioxide needed to produce 28.8 g of oxygen = 28.8×160/96 = 48 grams
