A simple electromagnet consisting of a coil of insulated wire wrapped around an iron core<span>. A </span>core<span> of ferromagnetic material like </span>iron<span> serves to increase the magnetic field created. The strength of magnetic field </span>generated<span> is proportional to the amount of </span>current<span> through the winding.</span>
Answer:
The time taken by the car is 8.94 seconds.
Answer:
Explanation:
We can use the following kinematics equations to solve this problem:
.
Using the first one to solve for acceleration:
.
Now we can use the second equation to solve for the distance travelled by the airplane:
(three significant figures).
Answer:
Understanding projections and coordinate systems important knowledge to have, especially if you deal with many different sets of data that come from different sources. Projections Distortion Coordinate Systems Datums
A Cartesian coordinate system. Locations on the Earth's surface are measured and represented in terms of coordinates; a coordinate is a set of two or more numbers that specifies the position of a point, line, or other geometric figure in relation to some reference system.
• Check Layer Properties > Source > Spatial Reference to find out what coordinate system your data is in. If it says “Unknown Coordinate System” you definitely want to use the Define Projection tool. • The Define Projection tool will not make a copy of your data.
Math coordinates identify the location of a point on a graph or map. The ordered pair, (x,y) is the address of the point. The Cartesian coordinate system is the graph used to locate the point.
Explanation:
Answer:
Explanation:
Using the formula to calculate the maximum height
H = u²/2g
u is the initial velocity = 18m/s
g is the acceleration due to gravity = 9.81
H = 18²/2(9.81)
H = 324/19.62
H = 16.51m
The maximum height in which the ball reached from the ground = 85m + 16.51m = 101.5m
b) Time of fight = 2u/g
T = 2(18)/g
T = 36/9.81
T = 3.67s
It took the ball 3.67s later to reach the ground
3) To get the final velocity of the ball as it hits the ground, we need to calculate the horizontal component of the velocity,
Ux = Ucosθ
ux = 18cos 90 (angle of launch is 90 since the ball is thrown vertically upwards)
Ux = 18(0)
Ux = 0m/s
Hence the final velocity of the ball as it hits the ground is 0m/s