At position of maximum height we know that the vertical component of its velocity will become zero
so the object will have only horizontal component of velocity
so at that instant the motion of object is along x direction
while if we check the acceleration of object then it is due to gravity
so the acceleration of object is vertically downwards
so it is along y axis
so here these two physical quantities are perpendicular to each other
so correct answer would be
<em>C)At the maximum height, the velocity and acceleration vectors are perpendicular to each other. </em>
Given Information:
Length of wire = 132 cm = 1.32 m
Magnetic field = B = 1 T
Current = 2.2 A
Required Information:
(a) Torque = τ = ?
(b) Number of turns = N = ?
Answer:
(a) Torque = 0.305 N.m
(b) Number of turns = 1
Explanation:
(a) The current carrying circular loop of wire will experience a torque given by
τ = NIABsin(θ) eq. 1
Where N is the number of turns, I is the current in circular loop, A is the area of circular loop, B is the magnetic field and θ is angle between B and circular loop.
We know that area of circular loop is given by
A = πr²
where radius can be written as
r = L/2πN
So the area becomes
A = π(L/2πN)²
A = πL²/4π²N²
A = L²/4πN²
Substitute A into eq. 1
τ = NI(L²/4πN²)Bsin(θ)
τ = IL²Bsin(θ)/4πN
The maximum toque occurs when θ is 90°
τ = IL²Bsin(90)/4πN
τ = IL²B/4πN
torque will be maximum for N = 1
τ = (2.2*1.32²*1)/4π*1
τ = 0.305 N.m
(b) The required number of turns for maximum torque is
N = IL²B/4πτ
N = 2.2*1.32²*1)/4π*0.305
N = 1 turn
Search Results
Featured snippet from the web
Work is the force on the object as it changes a distance. Interestingly, as work is done on an object, potential energy can be stored in that object. For example, if you carry a load up the stairs. Now that load will have potential energy that can be transformed into kinetic energy and so on
I would say clay, because its a solid
Answer:
6.88 m/s
Explanation:
The Conservation of Energy states that:
Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy
So we can write
We can cancel the common factor of 
which leaves us with
Lets solve for 
Subtract 
from both sides of the equation.
Multiply both sides of the equation by 2.
Simplify the left side.
Apply the distributive property.
Cancel the common factor of 2.
Take the square root of both sides of the equation to eliminate the exponent on the right side.
We are given 
.
We can now solve for the final velocity.
Anything multiplied by 0 is 0.
