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Sedaia [141]
3 years ago
10

A fluid has a density of 921 kg/m^3. at a depth of 1.22 m, the fluid pressure is 122,000 Pa. what is the pressure at the top of

the fluid?(unit=Pa) PLEASE HELP
Physics
1 answer:
Igoryamba3 years ago
3 0

Answer:

111,000 Pa

Explanation:

P = Patm + ρgh

122,000 Pa = Patm + (921 kg/m³) (9.8 m/s²) (1.22 m)

Patm = 111,000 Pa

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german

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3 0
3 years ago
when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in pa
liberstina [14]

Let  R₁  and R₂ be the  two Resistance

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

I = O.31A ( in series)

I  = 1.6 A ( in parallel)

when two resistance connected in series

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω   (equation1.)

When two resistance connected in parallel

    R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2}  }

V = I Rp

V=  I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω  

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

 (R₁ - R₂ ) ²  = (38.70) ²  - 4x 290.25

 (R₁ - R₂ ) ²   = 336.69  Ω  

R₁ - R₂ = 18.34     (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω  

Using the value of  R₁ in equation 1 we get

R₂ = 38·700 -  28.535

RR₂ = 10.125 Ω  

R₁ = 28. 535 v  and   R₂  10.125 Ω  

To know more about resistance in series and parallel:

brainly.com/question/27882579

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7 0
1 year ago
Calculate the frequency of the wave shown below.
jenyasd209 [6]

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

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Hope Helps!

5 0
2 years ago
A 286-kg motorcycle is accelerating up along a ramp that is inclined 31.6° above the horizontal. The propulsion force pushing th
kkurt [141]

Answer:

The acceleration motorcycle

a = 5.13 m / s²

Explanation:

Now to determine the acceleration of the motorcycle

Use the force to analysis motion

∑ F = m * a

∑ F = E - D - m*g * sin ( β ) = m * a

E = 3168 N

D = 230 N

β = 31.6 °

3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) = 286 kg * a

Now solve to a'

a = [ 3168 N - 230 N - 286 kg * 9.8  m / s² * sin ( 31.6° ) ] / (286 kg)

a = 5.13 m / s²

7 0
3 years ago
A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
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