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Arisa [49]
3 years ago
9

I need help answering this question in the photo (middle)

Physics
1 answer:
GalinKa [24]3 years ago
3 0
I believe it is because of weight if Timmy is larger and bigger than Maria that would mean he would stop slower just because of his bodyweight pushing on the back of the skateboard while Maria is all those skinny and she doesn’t have as much weight as she can go farther
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. What is the relationship between potential energy, kinetic energy, and speed as the skater moves down and up the U-shaped ramp
kykrilka [37]
Top of the U ramp: potential energy is the highest, while kinetic energy is the lowest

Bottom of the U ramp(aka the curve part): potential energy is the lowest and the kinetic energy is the highest

THEREFORE, PE and KE have an INVERSE RELATIONSHIP.
6 0
3 years ago
Read 2 more answers
Help! <br><br><br>I'm not sure my answer is correct.<br><br><br>Problem is attached!​
kaheart [24]
  • Let G be xN

\\ \sf\longmapsto x-20=30

\\ \sf\longmapsto x=30+20

\\ \sf\longmapsto x=50N

Option B

3 0
2 years ago
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A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed
Ronch [10]

Answer:5.7m/s

Explanation:

Mass=1kg

Initial velocity=u=8m/s

height=h=1.6m

Final velocity =v

Acceleration due to gravity=g=9.8m/s^2

v^2=u^2-2xgxh

v^2=8^2-2x9.8x1.6

v^2=8x8-2x9.8x1.6

v^2=64-31.36

v^2=32.64

Take the square root of both sides

√(v^2)=√(32.64)

v=5.7

Speed at the height of 1.6m is 5.7m/s

8 0
3 years ago
How can inclined planes change the amount of force to move an object? A. Increase height of the inclined plane B. Increase dista
mash [69]

Answer:

Option ( B ) is correct .

Explanation:

To lift a heavy weight , inclined plane is used . Use of inclined plane , makes the task easier because instead of force mg , force mg sinθ is to be used which is less than mg . Here θ is inclination of inclined plane.

If h be the height by which weight is to be lifted

potential energy acquired by weight = mgh

work done by force mg sinθ = mgsinθ x d where d is displacement required .

mg sinθ x d = mgh  ( work done by force = potential energy stored in luggage )

d = h / sinθ

d will be more than h

Hence inclined plane increases the distance to be covered by force applied though it decreases the force itself.

Hence option ( B ) is correct .

4 0
3 years ago
A solid uniform cylinder of mass 4.1 kg and radius 0.057 m rolls without slipping at a speed of 0.79 m/s. What is the cylinder’s
Amiraneli [1.4K]

Answer:

The cylinder’s total kinetic energy is 1.918 J.

Explanation:

Given that,

Mass = 4.1 kg

Radius = 0.057 m

Speed = 0.79 m/s

We need to calculate the linear kinetic energy

Using formula of linear kinetic energy

K.E_{l}=\dfrac{1}{2}mv^2

K.E_{l}=\dfrac{1}{2}\times4.1\times(0.79)^2

K.E_{l}=1.279\ J

We need to calculate the rotational kinetic energy

K.E_{r}=\dfrac{1}{2}\times I\omega^2

K.E_{r}=\dfrac{1}{2}\times\dfrac{1}{2}\times mr^2\times(\dfrac{v}{r})^2

K.E_{r}=\dfrac{1}{4}\times m\times v^2

K.E_{r}=\dfrac{1}{4}\times4.1\times(0.79)^2

K.E_{r}=0.639\ J

The total kinetic energy is given by

K.E=K.E_{l}+K.E_{r}

K.E=1.279+0.639

K.E=1.918\ J

Hence, The cylinder’s total kinetic energy is 1.918 J.

8 0
3 years ago
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