The distance traveled by the wood after the bullet emerges is 0.16 m.
The given parameters;
- <em>mass of the bullet, m = 23 g = 0.023 g</em>
- <em>speed of the bullet, u = 230 m/s</em>
- <em>mass of the wood, m = 2 kg</em>
- <em>final speed of the bullet, v = 170 m/s</em>
- <em>coefficient of friction, μ = 0.15</em>
The final velocity of the wood after the bullet hits is calculated as follows;

The acceleration of the wood is calculated as follows;

The distance traveled by the wood after the bullet emerges is calculated as follows;

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.
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Answer: Friction also prevents an object from starting to move, such as a shoe placed on a ramp. When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy. Friction can sometimes be useful.
Explanation:
Answer: 1479watts
Explanation:
Power is defined as the energy expended or work done in a specific time.
Mathematically,
Power = Workdone/time taken
Since work done is force × distance
Power = force × distance/time
Force = Mary's weight = 87N
Distance = height of the flight = 102meters
Time = 6.0seconds
Substituting in the formula we have;
Power = 87 × 102/6
Power = 1,479watts
Note that the time must be in seconds before usage. If its given in minutes, you will have to convert to seconds
Answer:
She will make the jump.
Explanation:
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
First we will consider horizontal motion of stunt women
Displacement = 77 m, Initial velocity = 28 cos 15 = 27.05 m/s, acceleration = 0
Substituting

So she will cover 77 m in 2.85 seconds
Now considering vertical motion, up direction as positive
Initial velocity = 28 sin 15 = 7.25 m/s, acceleration =acceleration due to gravity = -9.8
, time = 2.85
Substituting

So at time 2.85 stunt women is 10.11 m below from starting position, far side is 25 m lower. So she will be at higher position.
So she will make the jump.
A spring that obeys Hooke's law has a spring force constant of 272 N/m. This spring is then stretched by 28.6 cm