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Ronch [10]
3 years ago
8

A 10-lb weight is suspended from two accurate spring scales, each of which has negligible weight. What will be the weight readin

gs on the scales?
The top scale will measure 0 lb and the lower scale will measure 10 lb.

Both scales will measure 10 lb.

Each scale will measure 5 lb.

The lower scale will measure 0 lb and the top scale will measure 10 lb.
Physics
1 answer:
rjkz [21]3 years ago
4 0
<h2>Hello!</h2>

The answer is: Both scales will measure a weight 10 lb

<h2>Why?</h2>

From the options, we can know that both spring scales are in series:

It's like there are just one scale composed by two scales since the statement states that both has negligible weight, so both scales will be reading the whole weight.

Calculations:

T1=T2

Force = Tension - Weight = ma\\Tension - Weight = 0\\Tension = Weight

So, if tension is equal to weight, it means that both scales will be reading a weight of 10 lb.

Have a nice day!

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As more and more bulbs are connected in series to a flashlight battery, what happens to the brightness of each bulb? Assuming th
balu736 [363]

Answer:

P_1 = P_2 = \frac{P}{2}

so each bulb brightness becomes half of its given or indicated power

P_1 = P_2 = \frac{V^2}{R}

so both bulb will glow same power as indicated

Explanation:

Let the indicated power on the bulbs is given as P and its rated voltage is V

so here resistance of each bulb is given as

R = \frac{V^2}{P}

now if the two bulbs are connected in series so we will have

R_{eq} = R_1 + R_2

R_{eq} = 2\frac{V^2}{P}

now the current in the circuit is given as

i = \frac{V}{R_{eq}

i = \frac{P}{2V}

now brightness of each bulb is given as

P_1 = P_2 = i^2 R

P_1 = P_2 = \frac{P}{2}

so each bulb brightness becomes half of its given or indicated power

Now if the two bulbs are connected in parallel

then the net voltage across each bulb is "V"

so we will have

P_1 = P_2 = \frac{V^2}{R}

so both bulb will glow same power as indicated

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4 years ago
Need help ASAP
zhannawk [14.2K]

For number one, the answer is the first dash mark

And for number two, the answer is the 4th dash.

5 0
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_______ are pictures of relationships.
S_A_V [24]

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Graphs

Explanation:

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3 years ago
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A block of mass 10kg is suspendet at a diameter of 20cm from the centre of a uniform bar im long, what force is required to bala
lana [24]

Answer:

4 kg of force

Explanation:

Force = (mass x distance to fulcrum) / length of fulcrum to end

Subsitute values

F = (10 x 20)/50

F =4

4 0
3 years ago
There are 640 acres in a square mile. how many square meters are there in 7.80 acres.
lukranit [14]

Answer:

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

Explanation:

Conceptual analysis

Acre, square mile and square meter are area units, so their equivalences are in square units.

Known data

1 (mi)² = 640 acres

1 mi = 1609.34 m

Problem development

We know that 1 mile = 1609.34m, then: (1 mile)² = (1609.34m)²=(1609.34)²m²

We apply the known conversion factors to calculate the square meters (X) in 7.8 acres:

X=7.8 acres *\frac{(1 mi)^{2} }{640 acres} * \frac{(1609.34)^{2}m^{2}  }{(1 mi)^{2} }

We eliminate acres and square miles (mi²) because they are in the numerator and denominator, so the answer is in square meters (m²)

X=31565.3 m²

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

8 0
3 years ago
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