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3 years ago

How is Einstein's equation E = mc^2 used in medicine?

1 answer:

8 0

This equation is used in nuclear medicine. Nuclear medicine is the branch of medicine that deals with the use of radioactive substances in research, diagnosis, and treatment.

In physics, this equation is generally used in the nuclear physics. E = mc^2 gives the energy release during a nuclear reaction.

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1. Which object is farthest from the origin at t=2sec

Stolb23 [73]

Answer:

that one i know only pe not that sorry again

6 0

2 years ago

A calorimeter directly measures ______ in order to calculate ______. (1 point)

Aneli [31]

The complete sentence is:

A calorimeter directly measures changes in temperature in order to calculate specific heat.

In fact, the amount of energy acquired/released by a substance is directly proportional to its change in temperature due to the equation

$Q=mC_s \Delta T$

where Q is the amount of energy, m is the mass of the substance, Cs is the specific heat of the substance and $\Delta T$ is the change in temperature. Therefore, by knowing Q, m and by measuring the change in temperature, it is possible to calculate Cs, the specific heat capacity of the substance.

4 0

2 years ago

Read 2 more answers

Suppose that Hubble's constant were H0 = 51 km/s/Mly (which is not its actual value). What would the approximate age of the univ

bija089 [108]

Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Given the data in the question;

Hubble's constant; $H_0 = 51km/s/Mly$

Age of the universe; $t = \ ?$

We know that, the reciprocal of the Hubble's constant ( $H_0$ ) gives an estimate of the age of the universe ( $t$ ). It is expressed as:

$Age\ of\ Universe; t = \frac{1}{H_0}$

Now,

Hubble's constant; $H_0 = 51km/s/Mly$

We know that;

$1\ light\ years = 9.46*10^{15}m$

$1\ Million\ light\ years = [9.46 * 10^{15}m] * 10^6 = 9.46 * 10^{21}m$

Therefore;

$H_0 = 51\frac{km}{\frac{s}{Mly} } = 51000\frac{m}{s\ *\ Mly} \\\\H_0 = 51000\frac{m}{s\ *\ (9.46*10^{21}m)} \\\\H_0 = 5.39 *10^{-18}s^{-1}\\$

Now, we input this Hubble's constant value into our equation;

$Age\ of\ Universe; t = \frac{1}{H_0}\\\\t = \frac{1}{ 5.39 *10^{-18}s^{-1}} \\\\t = 1.855 * 10^{17}s\\\\We\ convert\ to\ years\\\\t = \frac{ 1.855 * 10^{17}}{60*60*24*365}yrs \\\\t = \frac{ 1.855 * 10^{17}}{31536000}yrs\\\\t = 5.88 *10^9 years$

Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Learn more: brainly.com/question/14019680

6 0

2 years ago

1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?

VARVARA [1.3K]

Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

North>>>East>>>South

Hence the displacement is defined as the distance away from the initial position is

Initial position =18km

FInal position = 16km

The displacement = 18-16= 2km

Hence the displacement is 2km

6 0

2 years ago

A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of

anyanavicka [17]

f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.

The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.

From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."

Learn more: brainly.com/question/731147

6 0

2 years ago