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AlekseyPX
4 years ago
14

What is the free body for the platform

Physics
1 answer:
AURORKA [14]4 years ago
8 0
Universal gravitional field free body for the platform
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A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0
3 years ago
If 478 watts of power are used in 14 seconds,how much work was done
zepelin [54]

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

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Power  = 478watts

Time  = 14s

So;

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Answer:

pressure, stress pascal N/m2

energy, work, quantity of heat joule N·m

power, radiant flux watt J/s

electric charge, quantity of electricity coulomb -

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3 years ago
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