Answer:
Explanation:
The <em>purchase price</em> is what Janice invested for every share.
Since the stock was priced at $31.82 per share and she received a $1.11 dividend per share, her investment was:
- $31.82 - $1.11 = $30.71 per share ← answer
This price is the cost for Janice, over which she shall calculate their returns (gains or losses) on the future, when she sells the shares, for instance.
The total investment of Janice was the number of shares multipled by the purchase price:
- 40 shares × ($31.82 - $1.11)/ share
- 40 shares × ($30.71) / share = $1,228.40 (total investment)
There are four processes in water cycle. Starting from the heat from the sun is the process of evaporation.
Evaporation: In this process, light from the sun evaporate water from oceans, rivers, lakes, ice and soil into water vapor. Water vapor molecules combine to form clouds.
Condensation: In this process, water vapor from clouds cool down and turns back into liquid water in the form of water droplets. These water droplets stays in the air. Precipitation: In this process, water droplets they combine in the air, they become too heavy to stay in the air. Therefore, they fall in the form of rain, snow or other form.
Collection: In this process, water that falls as rain, snow or other form comes back in the ocean, lakes, river or any other water body. Water will also be absorbed by soil and will be collected as ground water.
;D
Explanation:
Expression for rate of the given reaction is as follows.
Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]
Therefore, the reaction equations by putting the given values will be as follows.
![1.8 \times 10^{-5} = k[0.105]x [0.15]y](https://tex.z-dn.net/?f=1.8%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%5B0.105%5Dx%20%5B0.15%5Dy)
............. (1)
![7.2 \times 10^{-5} = k [0.105]x [0.30]y](https://tex.z-dn.net/?f=7.2%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.105%5Dx%20%5B0.30%5Dy)
........... (2)
![3.6 \times 10^{-5} = k [0.0525]x [0.30]y](https://tex.z-dn.net/?f=3.6%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.0525%5Dx%20%5B0.30%5Dy)
............ (3)
Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.
Therefore, expression for rate of the reaction is as follows.
Rate = ![k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y](https://tex.z-dn.net/?f=k%5BHgCl_%7B2%7D%5Dx%20%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5Dy)
Rate = ![k [HgCl2]1 [C_{2}O^{-2}_{4}]2](https://tex.z-dn.net/?f=k%20%5BHgCl2%5D1%20%5BC_%7B2%7DO%5E%7B-2%7D_%7B4%7D%5D2)
Hence, total order = 1 + 2 = 3
According to equation (1),
![1.8 \times 10^{-5} = k [0.105]1 [0.15]2](https://tex.z-dn.net/?f=1.8%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20k%20%5B0.105%5D1%20%5B0.15%5D2)
k = 
Thus, we can conclude that rate constant for the given reaction is .
