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Deffense [45]
3 years ago
13

Chemical X has a mass of 5 grams, and chemical Y has a mass of 10 grams. If the two chemicals are mixed and a complete chemical

reaction takes place, what is most likely the mass of the product? grams​
Chemistry
1 answer:
hjlf3 years ago
3 0

Answer:

15 grams

Explanation:

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A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond
ss7ja [257]

<u>Given:</u>

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

<u>To determine:</u>

The temperature change

<u>Explanation:</u>

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

Ans: The temperature change in kelvin is 20 K

3 0
2 years ago
¿Cuáles son las características de los materiales de laboratorio? Por ejemplo: exactitud, resistencia a la temperatura, etc.
boyakko [2]

Answer:

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7 0
2 years ago
Please help (30 points)
aleksandrvk [35]

1) is chemical Bonds

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7 0
2 years ago
Read 2 more answers
Assume the following potential energies for a Newman projection: anti Me/H or anti Me/Me = 0 kcal/mole; eclipsed H/H = 4 kcal/mo
kap26 [50]

Answer:

0 kcal/mole

Explanation:

The most stable Newman projection corresponds to the minimum potential energy: Answer (e) 0 kcal/mole

4 0
2 years ago
The ionic radius for Na+ is 0.097 ηm and for Cl- is 0.181 ηm, the absolute value of the charge for each ion is 1.6x10-19 C, ε_o=
Vanyuwa [196]

Answer:

B = (2.953 × 10⁻⁹⁵) N.m⁹

Explanation:

At equilibrium, where the distance between the two ions (ro) is the sum of their ionic radii, the force between the two ions is zero.

That is,

Fa + Fr = 0

Fa = - Fr

Fa = (|q₁q₂|)/(4πε₀r²)

Fr = -B/(r^n) but n = 9

Fr = -B/r⁹

(|q₁q₂|)/(4πε₀r²) = (B/r⁹)

|q₁| = |q₂| = (1.6 × 10⁻¹⁹) C

(1/4πε₀) = k = (8.99 × 10⁹) Nm²/C²

r = 0.097 + 0.181 = 0.278 nm = (2.78 × 10⁻¹⁰) m

(k|q₁q₂|)/(r²) = (B/r⁹)

(k × |q₁q₂|) = (B/r⁷)

B = (k × |q₁q₂| × r⁷)

B = [8.99 × 10⁹ × 1.6 × 10⁻¹⁹ × 1.6 × 10⁻¹⁹ × (2.78 × 10⁻¹⁰)⁷]

B = (2.953 × 10⁻⁹⁵) N.m⁹

6 0
3 years ago
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