Question

Assume the following potential energies for a Newman projection: anti Me/H or anti Me/Me = 0 kcal/mole; eclipsed H/H = 4 kcal/mole; eclipsed Me/Me = 8 kcal/mole; gauche H/H and gauche H/Me = 0 kcal/mole; gauche Me/Me = 4 kcal/mole For 2,3-dimethylbutane, when drawing a Newman projection viewing down the C2-C3 bond, what is the potential energy of the most stable Newman projection?

Answer 1

Answer:

0 kcal/mole

Explanation:

The most stable Newman projection corresponds to the minimum potential energy: Answer (e) 0 kcal/mole