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Andrews [41]
3 years ago
13

Name the type of wave labeled C

Physics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer:

Ultraviolet radiations are the waves that are produced from the surfaces that have an extremely high temperature. For example, the sun. It is comprised of a wavelength that ranges from 10 nm up to about 400 nm. The sun releases this UV radiation that gives about 10% of the total electromagnetic radiation.

These radiations are harmful to humans and organisms, which can cause various types of skin diseases. But it also provides vitamin D.

These radiations are divided into 3 types, and they are-

(a) Ultraviolet radiation A

(b) Ultraviolet radiation B

(c) Ultraviolet radiation C.

Hence, the letter C represents the UV radiation in the figure.

Anna35 [415]3 years ago
4 0

Ultraviolet rays is the answer

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3.2 x 10^8 Ω•m

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Lady_Fox [76]

Answer:

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a(t)=\frac{dv}{dt}

Since it is given that

v(t)=\frac{5}{\sqrt{t}}\\\\\therefore a(t)=\frac{d(\frac{5}{\sqrt{t}})}{dt}\\\\a(t)=5\times \frac{dt^{-\frac{1}{2}}}{dt}\\\\=\frac{-5}{2}t^{\frac{-1}{2}-1}\\\\\therefore a(t)=x''(t)=\frac{-2.5}{t^{\frac{3}{2}}}

Now by definition of velocity we have

v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt

Integrating on both sides we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int v(t)dt

Applying values we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c

To find the constant we note that at t=1 the particle is at x=12 Thus applying values in the above equation we get

c=12-10\\\therefore c=2\\\\x(t)=10\sqrt{t}+2

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Explanation:

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F=Gxy/r^2

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