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charle [14.2K]
3 years ago
6

In the reaction of Mg (s) + 2 HCl (aq) Imported Asset MgCl2 (aq) + H2 (g), what

Chemistry
2 answers:
Bond [772]3 years ago
7 0

Answer: Decrease in concentration of reactant

Explanation:

For a typical reaction of an acid with a metal, decrease in concentration of reactant (acid) would lead to decrease in formation of salt or hydrogen. Increase in the concentration would lead to increase in the formation of products.

Temperature and pressure also have little effect here since the reaction is spontaneous in nature

Pavlova-9 [17]3 years ago
4 0

To decrease the rate of the forward reaction you can do the following:

- decrease the concentration of the reactants

- increase the concentration of the products

- increase the pressure so the hydrogen gas will not be easily removed from the reaction

- decrease the temperature, number of collisions will decrease so the rate of the reaction will decrease

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In a cooking context, which of the following materials is the best heat conductor?
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Write a procedure for "how to crack an egg" in cooking. You must have at least 3 steps. The format of your procedure is more imp
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Here's the procedure to Crack an egg ~

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6 0
2 years ago
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




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