Answer
When a body moves in projectile motion it has two components. One of the components is a horizontal component of the velocity and another is a vertical component.
The velocity along the horizontal component does not change because there is no acceleration long horizontal component.
Whereas velocity along vertical direction keeps on changing because the acceleration due to gravity is acting on the object. At a maximum height of the projectile velocity is equal to zero.
Answer:
Increasing speed.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;

In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.
The answer is B. Transfer electrons
Answer:
t = 0.85[s]
Explanation:
To solve this problem we must make a complete description of this. By doing an internet search, we find the description of this problem as if of the question.
<u>Description</u>
<u />
"An alligator swims to the left with a constant velocity of 5 m s when the alligator season a bird straight ahead the alligator speeds up with a constant acceleration of 3 m/s^2 leftward until it reaches a final velocity of 35 Ms left work how many seconds does it take the alligator to speed up from 5 m/s to 35 m/s".
To solve this problem we must identify the initial data:
v0 = initial velocity = 5 [m/s]
a = acceleration = 3 [m/s^2]
vf = final velocity = 35[m/s]
t = time = ?
Using the following kinematic equation, we can find the time that is required.
![v_{f}=v_{0}+a*t\\35=5+35*t\\t=\frac{35-5}{35} \\t=0.85[s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7B0%7D%2Ba%2At%5C%5C35%3D5%2B35%2At%5C%5Ct%3D%5Cfrac%7B35-5%7D%7B35%7D%20%5C%5Ct%3D0.85%5Bs%5D)