Answer:
Option c. Correlational
Explanation:
Correlational research is basically a method of carrying out a research where an experiment can not be conducted and where a researcher has to figure out that whether the two variable are in association with each other and if these are related then in what way the association between these two exists without any manipulation from the researcher's end.
It seeks to understand, measure and make assessment of the relationship or
association between these variables but can not find out if a variable is caused by the other variable.
<span>C) mountains; two continental plates meet at a convergent boundary</span>
Answer:
~218 electrons
Explanation:
(-3.5 * 10^-17 C)/(-1.602 * 10^-19 C) = 3.5/1.602x10^-2 = 218.47...
Answer:
a) 725.5 m
b) 630 m
Explanation:
Given data:
acceleration of Helicopter = 7.0 m/s^2
time spent upwards by helicopter = 11.0 seconds
a) Determine the maximum height above ground reached by the helicopter
h1 = at^2 /2
= 7 * 11^2 / 2
= ( 7 * 121 ) / 2 = 423.5 m
also v = a*t = 7 * 11 = 77 m/s
also we calculate h2
h2 = v^2 / 2g
= (77^2) / 2 * 9.81
= 302 m
therefore the maximum height = 302 + 423.5 = 725.5 m
b) Given that ; power deploys a jet pack strapped on his back at 7.0 s and with a downward acceleration of ; 1.0 m/s^2
<u>Determine distance Power reaches before helicopter crashes </u>
s = ut + 1/2 at^2
h.gt^2 - 77t - 423.5 m = 0
h.gt^2 - 77t = 423.5
t = 17. 66 secs
Yf = 423.5 + 77 *7 - 4.9 *7
Yf = 928.2
Vf = u + at
= 77 - 9.8*7 = 8.4 m/secs
t' = 17.66 - 7 = 10.66 secs
hence
Yf = 725.5 - 8.4 * 10.66 + 1/2 * -1 * 10.66
= 630 meters
Answer:
a) the mass of the second car = 28000 kg
b) the amount of kinetic energy that was lost in the collision = 
Explanation:
Given that:
mass of the train car 
= 6300 kg
speed of the train car 
= 12.0 m/s
mass of the second moving car 
= ???
speed of the second moving car 
= 2.2 m/s
After strike;
they both move with a speed 
= 4.00 m/s
a)
Using the conservation of momentum :
b)
To determine the amount of kinetic energy that was lost in the collision;
we will need to find the difference between the kinetic energy before the collision and after the collision;
i.e
Now; the kinetic energy that was lost in the collision is calculated as follows:
