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4 years ago

The diagram shows a vertical number line. what is the position of point X?

Physics

2 answers:

mihalych1998 [28]4 years ago

8 0

The correct answer is option 4, 16.

Explanation

Each division on the number line represents 4 units. The point X is located 4 divisions above 0, the origin. On this particular number line, 4 divisions represents $4\times 4=16$ units. This means that the point X is located at $y=16$ on the number line.

The correct answer is the 4th option, whose value is 16.

postnew [5]4 years ago

5 0

As per the question the diagram given is a vertical line.

We are asked to calculate the position of X.

Here the vertical line is divided into many segments.

As per the diagram, it is obvious that the points marked at different positions are separated by four units from each other i.e the distance between two successive marks is 4 units.

The point X is situated at four marks away from 0.

Hence the position of X will be= 4×4 units

= 16 units

Hence the correct answer of this question is D.

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A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.

WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

diameter of the mirror d = 1.7 m

height h = 180 km = 180 × 10³ m

wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

sin∅ = 3.588 × 10⁻⁷

we know that;

sin∅ = object separation / distance from telescope

object separation = sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷ × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

5 0

3 years ago

Hurricanes along the Gulf Coastal areas of Texas increase the rate of coastal erosion.

4vir4ik [10]

Answer:

its the last question

Explanation:

Thats because erosion takes away stuff

3 0

3 years ago

a lion is stalking an antelope that is running at a speed of 7m/s. At the moment the antelope passes the lion, she gives chase a

fiasKO [112]

Antelope: uniform motion => V = d/t => d = Vt = 7m/s * t

Lion: uniformly accelerated motion, with initial velocity = 0 => d = [1/2]a*t^2 = [1/2]*[5m/s^2]*t^2

7*t = 2.5*t^2=> 2.5t^2 - 7t =0 => t(2.5t - 7) = 0

2.5t - 7 = 0 => t = 7/2.5 = 2.8 m/s^2

7 0

3 years ago

Resistance and resistivity are related by a: 1.factor that is dependent on the length of the material 2.factor that is dependent

luda_lava [24]

Answer:

1. factor that is dependent on the length of the material.

2. factor that is dependent on the area of the material

Explanation:

Resistance R is directly proportional to its length L of an object and it is inversely proportional to the crossectional area of that object.

Mathematically, this is represented as:

a) Resistance R is directly proportional to its length L of an object

R ∝ L ......... Equation 1

b) Resistance R is inversely proportional to the crossectional area (A) of an object

R ∝ 1/A ............ Equation 2

Combining the two equations together, we have:

Resistance R is directly proportional to its length L of an object

R ∝ L/A .......... Equation 3

Resistivity of a material is the natural or inherent or intrinsic property that a material has. The Resistivity of a material is not dependent on the length or crossectional area of such material. It is only temperature dependent.

The resistance of a material is also dependent on the resistivity of the material. This means the resistance of a material is directly proportional to the resistivity of the material.

R ∝ ρ........Equation 4

Combining Equation 4 and 3 together, we have:

R = ρL/A

Where:

R = Resistance

ρ = Resistivity

L = Length of the material

A = Crossectional area of the material

Resistance and resistivity are related by a factor that is dependent on the length of the material a factor that is dependent on the area of the material

3 0

4 years ago

A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:

Alex

Answer:

The work done on the system can be accounted for by;

Both $E_g$ and $E_{int}$

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, $F_{NET}$ = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = $E_g$

The heat generated as internal energy to the system = $E_{int}$

Therefore;

The work done on the system = $E_g$ + $E_{int}$ .

6 0

3 years ago