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ser-zykov [4K]
1 year ago
13

a particle moves at a constant speed in a circular path. the instantaneous velocity and instantaneous acceleration vectors are:

Physics
1 answer:
Lilit [14]1 year ago
8 0

The instantaneous velocity always tangential to circular path and          instantaneous acceleration always points towards the center of circle.

What is instantaneous?

The definition of instantaneous velocity is the rate of change of location during a time that is virtually zero .The replica was. The definition of instantaneous velocity is the speed of a moving item at a certain instant in time.

The rate of change of location during a relatively brief period of time is known as instantaneous velocity.

In the limit when the time (and thus the displacement) between the two places approaches zero, the instantaneous acceleration is the average acceleration between two points on the route.

so, both of them are perpendicular to each other.

To learn about instantaneous velocity

brainly.com/question/1222392

#SPJ4

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Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s
Black_prince [1.1K]

The initial momentum of the system can be expressed as,

p_i=m_1u_1+m_{2_{}}u_2

The final momentum of the system can be given as,

p_f=m_1v_1+m_{2_{}}v_2

According to conservation of momentum,

p_i=p_f

Plug in the known expressions,

\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}

Thus, the final velocity of second mass is 2.99 m/s.

3 0
1 year ago
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Ne4ueva [31]

Answer:

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Explanation:

8 0
2 years ago
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A rocket ship starts from rest and turns on its forward booster rockets causing it to have a constant acceleration of 4 meters p
bagirrra123 [75]

Complete question is;

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 m/s² rightward. After 3s, what will be the velocity of the rocket ship?

Answer:

v = 12 m/s

Explanation:

We are given;

Initial velocity; u = 0 m/s (because ship starts from rest)

Acceleration; a = 4 m/s²

Time; t = 3 s

To find velocity after 3 s, we will use Newton's first equation of motion;

v = u + at

v = 0 + (4 × 3)

v = 12 m/s

6 0
3 years ago
Determine the elastic energy U stored in<br> the compressed spring.
hoa [83]

Answer:

Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.

Explanation:

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drek231 [11]

find acceleration force divided by Mass

a=f/m

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